虽然题目那么长其实就是把8进制的浮点数转换成10进制,为了练习Java Biginteger 类 我这里用的是Java,也可以用数组模拟. import java.math.BigDecimal; import java.math.RoundingMode; import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner cin = new Scanner(System.
把字符串数组转换为16进制字符串 import java.security.MessageDigest; public class StringUtil { public StringUtil() { super(); } public static String str; public static final String EMPTY_STRING = ""; private final static String[] hexDigits = { "0", &q
cmd清除命令:cls 之后查阅了其它博客,发现这位大神同样也在做JVM,并且我很希望用它的10进制转16进制类来测试一下该解析的10进制是否对应着Object的16进制呢? 这位大神的10进制转16进制代码: import java.io.BufferedReader; import java.io.File; import java.io.FileReader; public class Test { public static String txt2String(File file){ S
//十进制转十六进制 import java.util.Scanner; public class Main{ public static void main(String[] args){ Scanner input = new Scanner(System.in); int n; n=input.nextInt(); System.out.println(Integer.toHexString(n).toUpperCase());//转换成大写字母:toLowerCase():转换成小写的1
题意为进制转换,Java的大数类就像是作弊 import java.math.BigInteger; import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner in = new Scanner(System.in); int n=in.nextInt(); while(n!=0){ int a=in.nextInt(); int b=in.nextInt(); St
Problem Description Many classmates said to me that A+B is must needs. If you can't AC this problem, you would invite me for night meal. ^_^ Input Input may contain multiple test cases. Each case contains A and B in one line. A, B are hexadecimal num