题目链接 You are given a string, S, and a list of words, L, that are all of the same length. Find all starting indices of substring(s) in S that is a concatenation of each word in L exactly once and without any intervening characters. For example, given:
Map是Vim强大的一个重要原因,可以自定义各种快捷键,用起来自然得心应手. vim里最基本的map用法也就是 :map c a 这里把c映射成了a,在map生效的情况下,按下c就等同于按下了a 当然,常用的Ctrl,Shift,Alt自然也是支持的. 令Ctrl+a对应到a :map <C-a> a 令Alt+a对应到a :map <A-a> a 令Ctrl+Alt+a对应到a :map <C-A-a> a 到此,我们已经可以做很多事情了. 但是map命令远不只这一种
面试题3 -- 搜索二维矩阵 写出一个高效的算法来搜索 m × n矩阵中的值. 这个矩阵具有以下特性: 1. 每行中的整数从左到右是排序的. 2. 每行的第一个数大于上一行的最后一个整数. public class Solution { /** * @param matrix, a list of lists of integers * @param target, an integer * @return a boolean, indicate whether matrix contains
Cube number on a tree Time Limit: 20000/10000 MS (Java/Others) Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 1628 Accepted Submission(s): 382 Problem Description The country Tom living in is famous for traveling. Every year, man
()metamask-extension/app/scripts/controllers/transactions Transaction Controller is an aggregate of sub-controllers and trackers exposed to the MetaMask controller. 交易控制器是暴露于metamask控制器的子控制器和跟踪器的集合 txStateManager responsible for the state of a transa