package faceobject; import java.util.Arrays; public class Test { /** 加密问题 数据是小于8位的整数 先将数据倒序,然后将每位数字都加上5,再用除以10的余数代替该数据 然后将第一个和最后一个调换位置 */ public static void main(String[] args){ int x=123456; jiami1(x); System.out.println(); jiami2(x); } public stati
A. Alex and broken contest time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output One day Alex was creating a contest about his friends, but accidentally deleted it. Fortunately, all the problems
split(String regex, int limit)方法,头一个参数String regex表示字符串分割的模式,包括分隔符和正则表达式:但是第二个参数limit比较迷糊人,api中这样解释: limit 参数控制模式应用的次数,因此影响所得数组的长度.如果该限制 n 大于 0,则模式将被最多应用 n - 1 次,数组的长度将不会大于 n,而且数组的最后一项将包含所有超出最后匹配的定界符的输入.如果 n 为非正,那么模式将被应用尽可能多的次数,而且数组可以是任何长度.如果 n 为 0,那
string与int之间的相互转换C++(转) #include<iostream> #include<string> #include<sstream> using namespace std; int main() { /////////////////////////// string 转为 int string str="1234"; int n; istringstream iss;//istringstream从string读入,和cin
string[][]和string[,] http://www.codewars.com/kata/56f3a1e899b386da78000732/train/csharp Write a function partlist that gives all the ways to divide a list (an array) of at least two elements in two non-empty parts. Each two non empty parts will be in
/// <summary> Convert a string of hex digits (ex: E4 CA B2) to a byte array. </summary> /// <param name="s"> The string containing the hex digits (with or without spaces). </param> /// <returns> Returns an array of