Ultra-QuickSort Time Limit: 7000MS Memory Limit: 65536K Total Submissions: 34470 Accepted: 12382 题目链接:http://poj.org/problem?id=2299 Description In this problem, you have to analyze a particular sorting algorithm. The algorithm processes a sequen
题目链接 A. Currency System in Geraldion 有1时,所有大于等于1的数都可由1组成.没有1时,最小不幸的数就是1. #include<iostream> #include<cstdio> #include<algorithm> using namespace std; void solve(){ int n,x; scanf("%d",&n); ; ; i<=n; i++){ scanf("%
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1150 很经典的二分题目 就是求最小点覆盖集 二分图最小点覆盖集=最大匹配数 代码: #include<iostream> #include<cstdlib> #include<cstring> #include<cstdio> #define maxn 110 using namespace std; int ans; int n; int m; int k;