-- hive中解析json数组 select t1.status ,substr(ss.col,,) as col ,t3.evcId ,t3.evcLicense ,t3.evcAddress ,t3.modelName from ( select get_json_object(json,"$.status") as status ,split( regexp_replace( regexp_extract( get_json_object(json,"$.data&q
hive中建立外部分区表,外部数据格式是json的如何导入呢? json格式的数据表不必含有分区字段,只需要在hdfs目录结构中体现出分区就可以了 This is all according to this guide: http://blog.cloudera.com/blog/2012/12/how-to-use-a-serde-in-apache-hive/ hive> ADD JAR /home/hadoop/hive-serdes-1.0-SNAPSHOT.jar; Added /ho
using Newtonsoft.Json;using System;using System.Collections.Generic;using System.Linq;using System.Text;using System.Threading.Tasks; namespace Demo1113{ public sealed class Program { public static void Main() { SmsMess