最近参加项目中,数据操作基本都是用DataTable的操作,老代码中有些地方用到DataTable.Rows.Add又有些代码用的DataTable.ImportRow,于是就对比了一下 VS查询说明:显示 // // 摘要: // 创建使用指定值的行,并将其添加到 System.Data.DataRowCollection 中. // // 参数: // values: // 用于创建新行的值的数组. // // 返回结果: // 无. // // 异常: // System.Argument

今天写代码的时候用到ImportRow()向DataTable中添加记录,代码如下: DataTable dt = datatable;DataRow dr = dt.NewRow();dr["FileName"] = fileName;dr["DbName"] = DbName;dt.ImportRow(dr); 可是执行后发现dtAppendix中的记录并没有增加.可是将上述红色色代码换成dt.Rows.Add(dr);就可以了.后上网查了下资料弄清楚了原因.下

/// <summary> /// 构建测试数据表 /// </summary> /// <returns></returns> private DataTable GetTB() { //定义表结构 DataTable dt = new DataTable(); dt.Columns.Add("FactoryId"); dt.Columns.Add("FactoryName"); dt.Columns.Add(&qu

异常处理汇总-后端系列 http://www.cnblogs.com/dunitian/p/4523006.html 应用场景:ViewModel==>Mode映射的时候出错 AutoMappe r错误信息:Unmapped members were found. Review the types and members below.Add a custom mapping expression, ignore, add a custom resolver, or modify the sour

前言 我比较喜欢安静,大概和我喜欢研究和琢磨技术原因相关吧,刚好到了元旦节,这几天可以好好学习下EF Core,同时在项目当中用到EF Core,借此机会给予比较深入的理解,这里我们只讲解和EF 6.x中不同,相同的则不再叙述. EntityFramework Core 1.1方法理论详解 当我们利用EF Core查询数据库时如果我们不显式关闭变更追踪的话,此时实体是被追踪的,关于变更追踪我们下节再叙.就像我们之前在EF 6.x中讨论的那样,不建议手动关闭变更追踪,对于有些特殊情况下,关闭变更追

ASP.NET Core 引用外部程序包的时候,有时会出现下面的错误: The type 'Object' is defined in an assembly that is not referenced. You must add a reference to assembly 'mscorlib, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089'. Sample.Infrastructure..NETStan

本文转自:http://docs.nopcommerce.com/display/nc/How+to+code+my+own+shipping+rate+computation+method Go to start of metadata   In nopCommerce, administration menu is build from the Sitemap.Configuration file which is located in Nop.Admin folder. To do the

一.简介 这个示例详细介绍ALayout的add方法的使用(原理也适用于Linearlayout),以及add上去的新ui和已有的ui如何数据交换,初学者推荐.二.效果图 三.相关下载 https://github.com/do-project/code4do/tree/master/testALayoutAdd四.相关讨论 http://bbs.deviceone.net/forum.php?mod=viewthread&tid=512&extra=page%3D1五.更多案例http:

You are given two linked lists representing two non-negative numbers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not con

Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.

Given a string that contains only digits 0-9 and a target value, return all possibilities to add operators +, -, or * between the digits so they evaluate to the target value. Examples: "123", 6 -> ["1+2+3", "1*2*3"] "

Given a non-negative integer num, repeatedly add all its digits until the result has only one digit. For example: Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it. Follow up: Could you do it without an

Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +, -and *. Example 1 Input: "2-1-1". ((2-1)-1) = 0 (2-(1-1)) = 2 Output: 

You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. Input: (2 -> 4 -> 3) + (5 -> 6 ->

1. UIImage imageWithContentsOfFile卡顿 [[UIImage alloc] initWithContentsOfFile 卡顿 2.uitableview scroll to top NSIndexPath *indexPath = [NSIndexPath indexPathForRow:0 inSection:0]; [_commentsTab scrollToRowAtIndexPath:indexPath atScrollPosition:UITableV

发现问题 需求很简单,大致就是要批量往数据库写数据,于是打算用Parallel并行的方式写入,希望能利用计算机多核特性加快程序执行速度.想的很美好,于是快速撸了类似下面的一串代码: using (var db = new SmsEntities()) { Parallel.For(, , (i) => { db.MemberCard.Add(new MemberCard() { CardNo = "NO_" + i.ToString(), Banlance = , CreateT

[本文链接] http://www.cnblogs.com/hellogiser/p/add-two-numbers-without-arithmetic.html [题目] 写一个函数,求两个整数的之和,要求在函数体内不得使用+.-.×.÷. [分析] 这是一道考察发散思维的很有意思的题目.当我们习以为常的东西被限制使用的时候,如何突破常规去思考,就是解决这个问题的关键所在. 普通四则运算都不能用,那还能用什么啊?我们会想到位运算,因为四则运算本质上都可以通过位运算实现. 举个例子: 首先我们

分析:android 4.2.X及以下的版本,addHeaderView必须在setAdapter之前,否则会抛出IllegalStateException. android 4.2.X(API 17) ListView源码如下: public void addHeaderView(View v, Object data, boolean isSelectable) { if (mAdapter != null && ! (mAdapter instanceof HeaderViewLis

题目: You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. Input: (2 -> 4 -> 3) + (5 -> 6 -&

题目描述: You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. Input: (2 -> 4 -> 3) + (5 -> 6