二代reads最短都有50bp,所以大家常用的比对工具都是不支持50bp以下的reads的比对的. 但是,在实际中,我们确实又有比对super short reads的需求. So,我找到了如下方法来比对super short reads: 1.msa.sh,bbmap里的,好用,但是太慢. 2.bbduk.sh,bbmap里的,不支持输出sam文件,只能输出map和unmap的reads. 3.bbmap.sh,好用,超快,但是不支持mismatch,可惜. 4.seal.sh,没试过. 5.

首先介绍一下jqGrid是一个jQuery的一个表格框架,现在有一个需求就是将数据库表的数据拿出来显示出来,分别有id,name,details三个字段,其中难点就是details字段,它的数据是这样的'{"watchDomain":"xxx.com",....省略......"":""}',也就是json数据字符串,现在要把它显示在前端jqGrid表格上,列名就是json数据的Key值,值就是对应的value值,jqGrid

一.子查询 1.为什么要使用子查询:问题不能一步求解或者一个查询不能通过一步查询得到. 2.分类:单行子查询和多行子查询. 3.子查询的本质:一个查询中包含了另外一个或者多个查询. 4.使用子查询的规则: (1)可以在主查询的where.select.from.having的后面放置子查询,但是不可以在在group by后面防止子查询. (2)将子查询放到括号中去. (3)强调from后面放置子查询. (4)主查询和子查询使用的可以不是同一张表. (5)一般不在主查询中使用order by,但是

项目中需要将系统从SQLServer数据库迁移到Oracle上.由于原大部分数据访问操作都是通过包装了Entity Framework的统一访问入口实现的,所以需要研究Entity Framework从SQLServer转移到Oracle的实现方式. 自从EF4.X起,Oracle就为EF提供了驱动支持,但是很可惜的是不支持CodeFirst模式.庆幸的是从ODP.NET 11.2.0.3.0开始,Oracle官方提供了支持CodeFirst的纯托管代码的EF驱动.但是有以下几点是需要知道的;

No. 课程 备注 1 HANA概述 HANA 特点 2 HANA Server & Studio & Client 认识HANA Server \Client\ Studio, 熟悉开发工具 3 HANA的存储及对象 HANA的存储特性.介绍table,view,index,sequence,trigger,function等 4 HANA Modeling HANA建模 5 HDB SQLScript HANA SQLScript 6 User & Authorization

Common Subsequence Problem Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <x1, x2, ..., xm> another sequence Z = <z1, z2, ..., zk> is a subsequence of X if

题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=87730#problem/F 题目: Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, ..., xm > another sequence

问题来源:刘汝佳<算法竞赛入门经典--训练指南> P60 问题7: 问题描述:给两个子序列A和B,求长度最大的公共子序列.比如1,5,2,6,8,和2,3,5,6,9,8,4的最长公共子序列为5,6,8另一个解是2,6,8). 分析:设dp[i][j]为A1,A2,...,Ai和B1,B2,...,Bn的LCS长度,则状态转移方程为: if(A[i]==B[i]) d[i][j] = d[i-][j-]+; else d[i][j] = Max{d[i-][j],d[i][j-]}; 时间复杂

Common Subsequence Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 46387   Accepted: 19045 Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, ..

Common Subsequence Time Limit: 2 Sec  Memory Limit: 64 MBSubmit: 951  Solved: 374 Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <X1, x2, ..., xm>another sequence

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9595    Accepted Submission(s): 3923 Problem Description A subsequence of a given sequence is the given sequence with some elements (possible none

Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 18765    Accepted Submission(s): 7946 Problem Description A subsequence of a given sequence is the given sequence with some ele

1.切片: 通过指定下标的方式来获得某一个数据元素,或者通过指定下标范围来获得一组序列的元素,这种访问序列的方式叫做切片.    访问某一个数据元素的的语法如下:    sequence[index] sequence是序列名,index是想要访问的元素对应的偏移量,偏移量可以是正值,范围是:0<=index<=len(sequence)-1; 也可以是负值,范围是:-len(sequence)<=index<=-1 序列访问多个元素,只需给出开始和结束的索引值,并且用冒号分隔就可

利用自定义键盘,需要手动删除编辑框中的文本时,会根据光标的位置来删除字符.那么,如何来控制光标呢,android为我们提供了哪些方法,来处理光标呢? 这里提供几个自己写的方法,根据这些方法可以满足在光标任何位置删除字符的要求. // 往文本框中添加内容 public void addString(String sequence) { int index = getEditSelection();// 光标的位置 if (index < 0 || index >= getEditTextView

Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, ..., xm > another sequence Z = < z1, z2, ..., zk > is a subsequence of X if there exists a strictly

监控SQL 1.监控事例的等待: select event,sum(decode(wait_time,0,0,1)) prev, sum(decode(wait_time,0,1,0)) curr,count(*) from v$session_wait group by event order by 4; 2.回滚段的争用情况: select name,waits,gets,waits/gets ratio from v$rollstat a,v$rollname b where a.usn=

1.链接地址: http://poj.org/problem?id=1458 http://bailian.openjudge.cn/practice/1458/ 2.题目: Common Subsequence Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 35411   Accepted: 14080 Description A subsequence of a given sequence is the given

Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 20815    Accepted Submission(s): 8954 Problem Description A subsequence of a given sequence is the given sequence with some ele

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1159 Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 18201    Accepted Submission(s): 7697 Problem Description A subsequence of

Common Subsequence Problem Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <x1, x2, ..., xm> another sequence Z = <z1, z2, ..., zk> is a subsequence of X if

Common Subsequence Time Limit: 2 Seconds      Memory Limit: 65536 KB A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <x1, x2, ..., xm> another sequence Z = <z1, z2, ..., zk