这道题计算了三个数的最小公倍数 import java.util.Scanner; public class D { public static int gcd(int a,int b) { int max = a>b?a:b; int min = a<b?a:b; if(max%min != 0) { return gcd(min,max%min); } else return min; } public static int lcm(int a,int b) { return a*b/gc
Assignment Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1698 Accepted Submission(s): 901 Problem Description Last year a terrible earthquake attacked Sichuan province. About 300,000 PLA so
#include<iostream> using namespace std; //不推荐用goto,当然用它更快 //辗转相除法求两数的最大公约数 int gcd(long int a,long int b){ int x=a<b?a:b; //获得较小者,用来做循环的约束值 ;i<x;x++){ //循环 if(a>b){ int r=a%b;//取余数 ){//能否整除判断 return b;//可以便输出 }else{//否则进行下一轮的算法 a=b,b=r; } }
Dual Core CPU Time Limit: 15000MS Memory Limit: 131072K Total Submissions: 21453 Accepted: 9297 Case Time Limit: 5000MS Description As more and more computers are equipped with dual core CPU, SetagLilb, the Chief Technology Officer of TinySoft Co
描述 The Archeologists of the Current Millenium (ACM) now and then discover ancient artifacts located at vertices of regular polygons. The moving sand dunes of the desert render the excavations difficult and thus once three vertices of a polygon are di
妖怪题目,做到现在:2017/8/19 - 1:41…… 不过想想还是值得的,至少邻接矩阵型的Dinic算法模板get√ 题目链接:http://poj.org/problem?id=1815 Time Limit: 2000MS Memory Limit: 20000K Description In modern society, each person has his own friends. Since all the people are very busy, they communic
