Write a function to delete a node (except the tail) in a singly linked list, given only access to that node. Given linked list -- head = [4,5,1,9], which looks like following: Example 1: Input: head = [4,5,1,9], node = 5 Output: [4,1,9] Explanation:
public static void main(String[] args){ String[] a = new String[]{"1","5","3","7"}; String[] b = new String[]{"2","3","4"}; String[] arrResult = arrContrast(a, b);
ArrayList al = new ArrayList(); al.add("a"); al.add("b"); //al.add("b"); //al.add("c"); //al.add("d"); for (int i = 0; i < al.size(); i++) { if (al.get(i) == "b") { al.remove(i); i--; } }
题目描述 在一个排序的链表中,存在重复的结点,请删除该链表中重复的结点,重复的结点不保留,返回链表头指针. 例如,链表1->2->3->3->4->4->5 处理后为 1->2->5 代码如下:未进行优化 public class ListNode { int val; ListNode next = null; ListNode(int val) { this.val = val; } } public class Solution { //将所有重复的结
如何使用 Java 删除 ArrayList 中的重复元素 (How to Remove Duplicates from ArrayList in Java) Given an ArrayList with duplicate values, the task is to remove the duplicate values from this ArrayList in Java. import java.util.*; import java.util.stream.Collectors;
