var time = "2514484555"; //这只是事例,并不是实际的数据 function timeToString(time) { var datetime = new Date(); datetime.setTime(time); var year = datetime.getFullYear(); var month = datetime.getMonth() + 1 < 10 ? "0" + (datetime.getMonth() + 1)
1.问题现象Tomcat7+Spring4.1.4,返回json字符串时发生406错误 The resource identified by this request is only capable of generating responses with characteristics not acceptable according to the request "accept" headers. HTTP Status 406 - type Status report messa
最近在使用JQuery的ajax方法时,要求返回的数据为json数据,在处理的过程中遇到下面的几个问题,那就是采用不同的方式来生成json数据的时候,在$.ajax方法中应该是如何来处理的,下面依次来进行说明,由于本人使用的是asp.net,所以处理的页面都是采用.net来做的!其他的方式应该是相同的吧 首先给出要传的json数据:[{"demoData":"This Is The JSON Data"}] 1,使用普通的aspx页
Student st1 = new Student(1, "dg", 18, new Date()); Student st2 = new Student(2, "dg", 18, new Date()); Student st3 = new Student(3, "dg", 18, new Date()); Student st4 = new Student(4, "d
现象: 1.报错:There is a cycle in the hierarchy! 2.返回至前台的json不完整,字段丢失. 错误原因: eg:entity1的属性有list<entitiy2>,entity2的字段中也含有entity1,即常见的双向关联;引发的死循环 解决方案: 1.重写一个vo用于传输json 2.@JsonIgnore
格式:TO_CHAR(number,'format_model') 9 -->Represents a number 0 --> Forces a zero to be displayed . -->Prints a decimal point , --> Prints a comma as a thousands indicator select to_char(6000,'99,999.00') from dual; 6,000.00 select to_char(6000,