描述 You have n computers numbered from 1 to n and you want to connect them to make a small local area network (LAN). All connections are two-way (that is connecting computers i and j is the same as connecting computers j and i). The cost of connecting
开始了最小生成树,以简单应用为例hoj1323,1232(求连通分支数,直接并查集即可) prim(n*n) 一般用于稠密图,而Kruskal(m*log(m))用于系稀疏图 #include<iostream> //prim n^2 #include<cstdio> #include<cstring> using namespace std; const int inf=0x3f3f3f3f; int a[102][102];int dis[102];int mark
题目链接:1319: 球 参考:wustoj 1319 球-wust_tanyao,并查集 并查集系列:WUSTOJ 1346: DARK SOULS(Java)并查集 Description Icy is a lonely boy. He was so boring these days. So he started to play a game himself. First, he took a heap of balls with many different colors. ( One
畅通工程 Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 34605 Accepted Submission(s): 15333 Problem Description 省政府"畅通工程"的目标是使全省任何两个村庄间都可以实现公路交通(但不一定有直接的公路相连,只要能间接通过公路可达即可).经过调查评估,得到的统计表中列
Conscription Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 14661 Accepted: 5102 Description Windy has a country, and he wants to build an army to protect his country. He has picked up N girls and M boys and wants to collect them to b
过路费 [问题描述]在某个遥远的国家里,有 n 个城市.编号为 1,2,3,…,n.这个国家的政府修 建了 m 条双向道路,每条道路连接着两个城市.政府规定从城市 S 到城市 T 需 要收取的过路费为所经过城市之间道路长度的最大值.如:A 到 B 长度为 2,B 到 C 长度为 3,那么开车从 A 经过 B 到 C 需要上交的过路费为 3. 佳佳是个做生意的人,需要经常开车从任意一个城市到另外一个城市,因此 他需要频繁地上交过路费,由于忙于做生意,所以他无时间来寻找交过路费最低 的行驶路线.然
Building a Space Station Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 7469 Accepted: 3620 Description You are a member of the space station engineering team, and are assigned a task in the construction process of the station. You ar
Jungle Roads Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 23882 Accepted: 11193 Description The Head Elder of the tropical island of Lagrishan has a problem. A burst of foreign aid money was spent on extra roads between villages som
Network Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 16047 Accepted: 6362 Special Judge Description Andrew is working as system administrator and is planning to establish a new network in his company. There will be N hubs in the
Java实现并查集,合并时采用路径压缩算法. 如果合并时使用循环修改的方法,一次合并的时间复杂度就为N,无法接受 public class Union { public int[] id;//对应索引所在的集 public int[] sz;//所在集的size,合并时小集合大集 public int count; public Union(int N){ id = new int[N]; for(int i=0;i<id.length;i++){ id[i] = i; } }//初始化,每个节
