上代码: Person p1 = new Person("xiaoer",1); Person p2 = new Person("san",4); Map<Person,String> maps = new HashMap<Person,String>(); maps.put(p1, "1111"); maps.put(p2, "2222"); System.out.println(maps); map
近期在看dnsjava 源码的时候,不经意间发现一个自己没有想过的问题: HashMap 如何使用key去查找对应的value的,这个问题很难用语言描述的清楚,那就使用代码来进行说明吧! public class test { public static void main(String[] args) { a aa = new a(); b bb = new b(); Map<Object,Object> c = new HashMap<Object,Object>(); c.p
我们通常使用Collections.sort()方法来对一个简单的数据列表排序.但是当ArrayList是由自定义对象组成的,就需要使用comparable或者comparator接口了.在使用这两者进行排序之前,先尝试不实现任何接口来进行排序. 考虑下面的例子——有一个Student类,具有三个属性:name, rollno, age public class Student { private String name; private int rollno; private int age;
Occasionally the average developer runs into a situation where he has to map values of arbitrary types within a particular container. However the Java collection API provides container related parameterization only. Which limits the type safe usage o