java 正则匹配空格字符串 正则表达式截取字符串 需求:从一堆sql中取出某些特定字符串: 比如配置的sql语句为:"company_code = @cc and project_id = @pid ; update t set a = @aa,b=@bb,c=@cd,ttt=@ttt;update t2 set d=@bb"; 我要拿出所有的以@开头的作为变量,并且去重,则如下玩: ps:其中正则匹配空格是 “\s+” public class Test { public stat
在Java编程中,如何清除/删除空格? 以下示例演示如何使用Util.regex.Pattern类的matcher.replaceAll(stringname)方法来删除空格. package com.yiibai; import java.util.regex.Matcher; import java.util.regex.Pattern; public class RemovingWhitespaces { public static void main(String[] argv) { S
public class List1 { public static void main(String[] args) { String s = "abc nnn ooo/xzsxc bs"; System.out.println("原字符串:"+ s + "\n"); //把s字符串变成ss数组,然后根据空格截取字符串 String[] ss = s.split(" "); //把数组放进list里面,进行遍历,把数组里的每
public class List { public static void main(String[] args) { String s = "abc nnn ooo/xzsxc bs"; System.out.println("原字符串:"+s); System.out.println(); String a[] = s.split(" "); ArrayList b = new ArrayList(); for (int i = 0; i
public class StringUtil { public static String getStringNoBlank(String str) { if(str!=null && !"".equals(str)) { Pattern p = Pattern.compile("\\s*|\t|\r|\n"); Matcher m = p.matche