php再调用json_decode从字符串对象生成json对象时,如果使用[]操作符取数据,会得到下面的错误 错误:Cannot use object of type stdClass as array 产生原因: +展开 -PHP $res = json_decode($res); $res['key']; //把 json_decode() 后的对象当作数组使用. 解决方法(2种):1.使用 json_decode($d, true).就是使json_decode 的第二个变量设置为 tru
/** * Copyright (c) 2011-2015, James Zhan 詹波 (jfinal@126.com). * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * h
<script src="~/Content/Scripts/jquery-1.11.3.min.js"></script> <script> $(function () { var data = { GoThroughNo: "ABC00001", AwbList: [] }; for (var i = 0; i < 10; i++) { var hawbMapping = new Object(); hawbMappin
1.需要用到的包 2.实例 实体类 people package com.shore.entity; /** * @author DSHORE/2019-4-19 * */ public class People { private int pid; private String pname; private int age; private String job; private double sal; public People() { } public People(int pid, St