直接举例说明: int i = 15;//一个10进制数 string txt = Convert.ToString(i,16);//将上面10进制以16进制形式显示为f string s = "15";//一个字符串15 int i = Convert.ToInt32(s,16);//注意:这里并不是将15转换为16进制的F,而是将字符串“15”转为10进制的0x15这个数字,10进制为21; 讲一个字节数组转为16字节格式的字符串: string s = string.Empty;
public final static char[] BToA = "0123456789abcdef".toCharArray() ; 1.16进制字符串转为字节数组 /** * 把16进制字符串转换成字节数组 * @param hex * @return */ public static byte[] hexStringToByte(String hex) { int len = (hex.length() / 2); byte[] result = new byte[len];
如何将字符串中的10进制数和16进制数提取出来,看以下代码: #include <stdio.h> typedef char TUINT8 ; typedef int TUINT32; TUINT32 Read_DecNumber(const TUINT8* str); TUINT32 Read_HexNumber(const TUINT8* str); int main(void) { int ret = Read_DecNumber("1000"); int d = R
//字符串转成16进制代码function strToHexStr(str:string):string;varc:char;ss:string;i:integer;beginwhile str<>'' do begin c:=str[1]; ss:=ss+format('%0x',[ord(c)]); delete(str,1,1);end;strtohexStr:= ss;end; //16进制字符串转换成字符串function HexStrToStr(const S
A+B Coming Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 9461 Accepted Submission(s): 6173 Problem Description Many classmates said to me that A+B is must needs.If you can’t AC this problem