/** * 获取URL中指定参数的值 * * @param name 参数名称 * @returns */ function getQueryString(name) { var reg = new RegExp('(^|&)' + name + '=([^&]*)(&|$)', 'i'); var r = window.location.search.substr(1).match(reg); if (r != null) { return unescape(r[2]); } r
JDBC URL FOR ORACLE, wrong or correct, how do you know? INSTANCE SID by ":" jdbc:oracle:thin:@db_ip_or_name:1521:ODB_IS SERVICE NAME by "/" jdbc:oracle:thin:@db_ip_or_name:1521/ODB_SN How do you know? SELECT NAME,VALUE,DESCRIPTION FROM
js中获取URL中指定的搜索字符串,主要利用location对象实现,废话少说,上代码. function getSearchString(key) { // 获取URL中?之后的字符 var str = location.search; str = str.substring(1,str.length); // 以&分隔字符串,获得类似name=xiaoli这样的元素数组 var arr = str.split("&"); var obj = new Object()
1.js获取域名的方法 1) var domain = document.domain 2) var domain = window.location.host 2.获取url的方法 1) var url = window.location.href 2) var url = self.location.href 3) var url = document.URL 4) var url = document.location 3.获取url中指定参数值 function getParams(na