需求:#将数字填充到对应金额单中 select substr(b.payMoney,length(b.payMoney),1) 分, substr(b.payMoney,length(b.payMoney)-1,1) 角, case when length(b.payMoney)-3 <=0 then '' else substr(b.payMoney,length(b.payMoney)-3,1) end 圆, case when length(b.payMoney)-4 <=0 then
function toDecimal2(x) { var f = parseFloat(x); if (isNaN(f)) { return false; } var f = Math.round(x*100)/100; var s = f.toString(); var rs = s.indexOf('.'); if (rs < 0) { rs = s.length; s += '.'; } while (s.length <= rs + 2) { s += '0'; } return s;
import java.math.BigDecimal; import java.text.DecimalFormat; import java.text.NumberFormat; public class format { double f = 111231.5585; public void m1() { BigDecimal bg = new BigDecimal(f); double f1 = bg.setScale(2, BigDecimal.ROUND_HALF_UP).doubl
1,下面是一个浮点类型的数字转成String字符串的例子 1 2 var f = 123.32342342 var s:String = "\(f)" //123.32342342 2,如果要保留两位小数 1 2 var f = 123.32342342 var s = String(format: "%.2f", f) //123.32
格式化数字保留两位小数点实现的方法有很多,在接下来的文章中将为大家详细介绍下如何使用js来实现 a = a.toFixed(2);//保留2位但结果为一个String类型 a = parseFloat(a);//将结果转换会float //用一步的话如下 a = parseFloat(a.toFixed(2));
#数字转字符保留几位小数 by gisoracle #数字转字符保留几位小数 by gisoracle def floattostr(num,xsnum): if xsnum==0: return str(int(num)) nd=round(num,xsnum) nstr=str(nd) idx=nstr.index('.') print idx p=len(nstr)-idx-1 print p n=xsnum-p print n s="" for i in range(n): s
1.数字前端去0 var num = number.replace(/\b(0+)/gi,"") 2.文字去除空格 var str = str.replace(/(^\s*)|(\s*$)/g, "") 3.截取字符串 var str = abcdef str = str.substr(2,3) //cde 4.保留小数 //保留4位小数 var number = 12.3321432; number = String(number).replace(/^(.*\.
/* * @descript: 保留两位小数,如果小数点大于两位小数,就向上取值保留两位小数<br/> * @time 2016-07-13 */function mathCeil(number){ var result = Number(number); text = result.toString(); var pointIndex = text.indexOf("."); if(pointIndex != -1){ var poi