//------[获取两个日期中所有的月份中] function getMonthBetween(start,end){ var result = []; var s = start.split("-"); var e = end.split("-"); var min = new Date(); var max = new Date(); min.setFullYear(s[0],s[1]); max.setFullYear(e[0],e[1]); console
var stime = '2018-07-25'; //开始日期 var etime = '2018-08-02'; //结束日期 getdiffdate(stime,etime); //获取两日期之间日期列表函数 function getdiffdate(stime,etime){ //初始化日期列表,数组 var diffdate = new Array(); var i=0; //开始日期小于等于结束日期,并循环 while(stime<=etime){ diffdate[i] = sti
<body onload="myFunction()"> <p id="demo"></p> <script> function myFunction(){ var nowDate = new Date(); var EndDate=new Date("2020-10-01 10:30:00") var dateDiff=EndDate.getTime()-nowDate.getTime(); va
1. 最笨的办法 function get() { var s = 22.127456 + ""; var str = s.substring(0,s.indexOf(".") + 3); alert(str); } 2. 正则表达式效果不错 <script type="text/javascript"> onload = function(){ var a = "23.456322"; var aNew; var
function getMonthBetween(startDate,endDate){ startDate=new Date(startDate.replace(/-/g,'/')); endDate=new Date(endDate.replace(/-/g,'/')); var num=0; var year=endDate.getFullYear()-startDate.getFullYear(); num+=year*12; var month=endDate.getMonth()-s
function judgeDivisor(m, n) { var num = {}; var i = 0; var x = parseInt(m / n); m = m % n; var result = ""; while (m != 0 && !(m in num)) { num[m] = i++; result += parseInt(m * 10 / n); m = m * 10 % n; } return m == 0; } 方法取自