function GetRequest() { var url = location.search; //获取url中"?"符后的字串 var theRequest = new Object(); if (url.indexOf("?") != -1) { var str = url.substr(1); strs = str.split("&"); for(var i = 0; i < strs.length; i ++) { t
网上说了一些jsonp的示例,感觉都没用,最后研究了一下,调用腾讯的一个api.最后要加output=jsonp&callback=?这个,比较适用. var url = "http://apis.map.qq.com/ws/place/v1/search?boundary=nearby(39.908491,116.374328,1000)&keyword=%E6%88%90%E9%83%BD&key=OB4BZ-D4W3U-B7VVO-4PJWW-6TKDJ-WPB77