var format = function (time, format) { var t = new Date(time); var tf = function (i) { return (i < 10 ? '0' : '') + i }; return format.replace(/yyyy|MM|dd|HH|mm|ss/g, function (a) { switch (a) { case 'yyyy': return tf(t.getFullYear()); break; case 'M
dctb:array[1..2,1..38] of Single=((0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0), (0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0) ):
有时候我们会不给C++类成员变量赋初始值,或是因为忘记在构造函数中指定(C++11可以写在类内),或是觉得没有必要写.然而,因为觉得编译器会把变量赋成0而不写是错误的.本文通过C++标准来解释这个问题. 本文基于N3337(C++11草案)标准. 关于没有初始化器的对象,在8.5-11中有提及: If no initializer is specified for an object, the object is default-initialized; if no initialization
//全局变量 var format = ""; //构造符合datetime-local格式的当前日期 function getFormat(){ format = ""; var nTime = new Date(); format += nTime.getFullYear()+"-"; format += (nTime.getMonth()+1)<10?"0"+(nTime.getMonth()+1):(nTime.