package wac.wev.as;//新建一个方法在求最大值import java.util.Scanner; public class MaxLian {public static void main(String[] args){//键盘录入以及导包Scanner sc= new Scanner(System.in);//数据接收System.out.println("请输入第一个数据:");int a = sc.nextInt();System.out.println(&qu
Console.WriteLine("请输入第一个数:"); int a = Convert.ToInt32( Console.ReadLine()); Console.WriteLine("请输入第二个数:"); int b = Convert.ToInt32(Console.ReadLine()); Console.WriteLine("请输入第三个数:"); int c = Convert.ToInt32(Console.ReadLine(
整理出自项目中一个需求,求两个数之间的数字. const week = function(arr,arr2){ let a=parseInt(arr); let b=parseInt(arr2); let c = []; if (arr - b < 0) { const number = Math.abs(a - b) + 1; for (let i = a; i < a + number; i++) { c.push(i); } } else if (a - b === 0) { c.pus
#include<stdio.h> int max(int a,int b,int c); int main() { int a,b,c; while(scanf("%d %d %d",&a,&b,&c)!=EOF){ printf("%d\n",max(a,b,c));} ; } int max(int a,int b,int c) { int m; m=a; if(b>m) m=b; if(c>m) m=c; re
题目: Given an integer array, find three numbers whose product is maximum and output the maximum product. Example 1: Input: [1,2,3] Output: 6 Example 2: Input: [1,2,3,4] Output: 24 分析: 给定一个数组,返回其中三个元素乘积的最大值. 注意的是,这道题是可以有负数出现,且是求三个数的乘积,所以我们需要考虑负数的情况. 最先
我是怎么想的,我前面学过两个数比大小,比如有三个数,a b c,先比较a和b的大小,然后用那个较大的和c比较就得出最大的那个了.这个求三个数比大小的问题最后变化成 了两个数比大小了. int main() { int a = 0; int b = 0; int c = 0; int max2 = 0;//保存两个数中较大的那一个 int max3 = 0;//保存三个数中最大的那一个 scanf_s("%d %d %d",&a,&b,&c); //先找出a b中
Problem Description Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it. But I also don't want to use many numbers, so I'll choose three positive integers
