forEach()取出数组中2的倍数和3的倍数的数 //for IE if(!Array.prototype.forEach){ Array.prototype.forEach = function(callback, thisArg){ var T, k; if(this == null){ throw new TypeError(" this is null or not defined"); } var O = Object(this); var len = O.length &
public class Copy1 { public static void main(String[] args) { array1(); //如果不初始化元素,默认为0 int [][] a = new int [][]{{1,3,2,5,7},{5,9,3,4,2}}; int [][] b = new int [a[1].length][a.length]; for(int i=0;i<b.length;i++){ //数组的转置 for(int j =0;j<b[i].length
标题描述的有点僵硬,大概需求是,从目标数组中过滤掉我想要删除的元素集合,这里使用的是遍历+过滤器的组合,很方便,做个笔记! let old = ["AE_CN_SUPER_ECONOMY_G", "CAINIAO_EXPEDITED_ECONOMY", "CAINIAO_SUPER_ECONOMY_SG", "CAINIAO_SUPER_ECONOMY", "SINOTRANS_PY", "SUN
JS如何从一个数组中随机取出一个元素或者几个元素. 假如数组为 var items = ['1','2','4','5','6','7','8','9','10']; 1.从数组items中随机取出一个元素 //code from http://caibaojian.com/js-get-random-elements-from-array.html var item = items[Math.floor(Math.random()*items.length)]; 2.从前面的一篇随机数组中随机
1.代码如下: var toObject = function(a) { var o = {}; for (var i=0, j=a.length; i<j; i=i+1) { // 这里我调整了下, YUI源码中是i<a.length o[a[i]] = true; } return o; } var keys = function(o) { var a=[], i; for (i in o) { if (o.hasOwnProperty(i)) { // 这里, YUI源码中是lang.h