题目链接 Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative 大整数乘法 我们以289*785为例 首先我们把每一位相乘,得到一个没有进位的临时结果,如图中中间的一行红色数字就是临时结果,然后把临时结果从低位起依次进位.对于一个m位整数乘以
1 题目 Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 接口: public String multiply(String num1, String num2); 2 思路 大整数的乘法,不能够简单用Integer.valueOf(
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 题意:计算字符串对应数字的乘积.参考JustDoIT的博客. 思路:先用一维向量存放计算的中间值,中间值存放对应位置乘积的和(暂不考虑进位的情况):然后针对进位的情况,进行计算:注意要跳