Given a binary search tree and a node in it, find the in-order successor of that node in the BST. Note: If the given node has no in-order successor in the tree, return null. 这道题让我们求二叉搜索树的某个节点的中序后继节点,那么我们根据BST的性质知道其中序遍历的结果是有序的, 是我最先用的方法是用迭代的中序遍历方法,然后用
1.在前面板放置一个activex容器 2.插入activex控件 3.百度找到这个activex控件的属性和方法介绍 4.程序框图中右键activex控件,创建xxx类的方法或者xxx的属性:activex控件主要是依据方法和属性在labview中实现功能的 5.后续步骤编其他labview程序一样 下面以windows media player 为例说明 http://www.xuebuyuan.com/816450.html
Given a binary search tree and a node in it, find the in-order successor of that node in the BST. The successor of a node p is the node with the smallest key greater than p.val. Example 1: Input: root = [2,1,3], p = 1 Output: 2 Explanation: 1's in-or