//设置节假日的数组 var holiday = Array('2016-04-30','2016-05-01','2016-05-02','2016-06-09','2016-06-10','2016-06-11','2016-09-15','2016-09-16','2016-09-17','2016-10-1','2016-10-01','2016-10-02','2016-10-03','2016-10-04','2016-10-05','2016-10-06','201
--只是加了固定日期,可以根据需求给成变量形式(BY 少年工藤) -思路:根据日期区间循环判断每一天是周日(1).周六(7)不变,其他加1 1 DECLARE @DAY DATE,@COUNT INT ' ' BEGIN SET @COUNT=@COUNT+( END ) ,@DAY) END SELECT @COUNT
select (floor(days/7)*5+days%7 -case when 6 between wd and wd+days%7-1 then 1 else 0 end -case when 7 between wd and wd+days%7-1 then 1 else 0 end ) INTO str from (select datediff(e,s) as days,weekday(s)+1 as wd) as a; ELSE select (