1. 参数中直接加入%%,注意不需要加两个单引号,加了就会出错,因为系统会自动为字符串类型加上两个单引号 <select id="selectPersons" resultType="person" parameterType="person"> select id,sex,age,username,password from person where true <if test="username!=null&qu
Problem Description Last year summer Max traveled to California for his vacation. He had a great time there: took many photos, visited famous universities, enjoyed beautiful beaches and tasted various delicious foods. It is such a good trip that Max
防sql注入之模糊匹配中%._处理: StringBuilder sbSql = new StringBuilder(); sbSql.Append(@"SELECT * from tablename t where 1 = 1 "); string name = dictparameters["Name"].ToString(); //Name参数值 if(name.Contains("%") || name.Contains("_&
首先创建一个测试表: insert into test(tt) values('\\\\172.18.28.153'); 现在我想使用模糊匹配,查出以 “\\172” 开头的字符串. 需要使用like 因为"\"是转义字符,所以需要使用4个"\".语句如下: SELECT * from test where tt like '\\\\172%' ; 结果无法得到我想要的数据,按理说这个字符串经过转义后变成“\\172%”应该得到结果才对. 经过多次不同的尝试,最终成
使用“.+?”实现中间模糊匹配的代码: public class Test { public static void main(String[] args) { String str="总会在某一个回眸的时刻醉了流年,濡湿了柔软的心.总会有某一个回眸的时刻醉了流年,濡湿了柔软的心"; str=str.replaceAll("总会在.+?流年", "总会有某一个回眸的时刻醉了流年"); System.out.println(str); } } 注: