原文链接:http://1985wanggang.blog.163.com/blog/static/776383320121745626320/ a="one,two,three,four" 要将$a分割开,可以这样: OLD_IFS="$IFS" IFS="," arr=($a) IFS="$OLD_IFS" for s in ${arr[@]} do echo "$s" done 上述代码会输出 one
Oracle把逗号分割的字符串转换为可放入in的条件语句的字符数列 前台传来的字符串:'589,321' SELECT*FROM TAB_A T1 WHERE T1.CODE IN ( SELECT REGEXP_SUBSTR('589,321','[^,]+', 1, LEVEL) FROM DUAL CONNECT BY REGEXP_SUBSTR('SMITH,ALLEN,WARD,JONES', '[^,]+', 1, LEVEL) IS NOT NULL )
JS分割字符串并放入数组的函数: var InterestKeywordListString = $("#userInterestKeywordLabel").html(); var InterestKeywordListArr = []; var t = ''; for (var i = 0; i < InterestKeywordListString.length; i++) { var tmp = InterestKeywordListString.charAt(i);
//学生记录由学号和成绩组成,N名学生的数据已放入主函数中的结构体数组中,fun函数:把分数最低的学生数据放入数组b所指的数组中,分数最低的学生可能不止一个.人数返回. #include <stdio.h> #define N 16 typedef struct { ]; int s; } STREC; int fun( STREC *a, STREC *b ) { STREC *c; c = a; int min = c->s; ; ; i < N; i++) { c++; if
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head><meta http-equiv="Content-Typ
Grails的ajax使用json格式返回,在js中构造字符串时若放入<g:link>标签,字符串构造就会错误 如下就会发生错误,导致回调函数无法执行 function show(obj){ var id=obj.value; $.post("rtstudent",{id:id}, function(data){ var datas=eval(data); var str=""; $.each(datas,function(i,st){ str+='&l
package com.wangcf; /** * 把字符串"3,1,2,4"以","分割拆分为数组,数组元素并按从小到大的顺序排列 * @author fan * */ public class Test{ /** * 冒泡排序 * @param s * @return */ public int[] paixu(int[] s){ for (int i=s.length; i >0; i--) { int tem; for (int j = 0; j &l