字典序排序 给定一个整数 n, 返回从 1 到 n 的字典顺序. 例如, 给定 n =1 3,返回 [1,10,11,12,13,2,3,4,5,6,7,8,9] . 请尽可能的优化算法的时间复杂度和空间复杂度. 输入的数据 n 小于等于 5,000,000. 解题思路 用函数栈(递归)用来去完成字典序排序. import java.util.ArrayList; import java.util.List; public class Solution { public List<Integer
function selectNum(lowNum,upNum) { var num = upNum-lowNum+1; // Math.floor() 向下取整 return Math.floor(Math.random()*num+lowNum); } var result = selectNum(2,8); //2~8范围内的整数
package study01; import java.util.Scanner; public class Sort { /** * 需求:由键盘输入三个整数分别存入变量a.b.c,对他们进行 排序(使用if-else),并且从小到大输出 * */ public static void main(String[] args) { Scanner sc = new Scanner(System.in); System.out.print("a="); int a = sc.nextI
import java.util.Comparator; import java.util.ArrayList; import java.util.Collections; public class Tester { public static void main(String[] args) { ArrayList list = new ArrayList(); list.add("东海湾"); list.add("傲来"); list.add("东海湾
Next Permutation Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers. If such arrangement is not possible, it must rearrange it as the lowest possible order (ie, sorted in ascending ord
需求 列表中先根据某id进行排序,然后id相同的再按某属性进行排序.最终显示效果如图所示: 实现代码 var data.items = [ {'brand_id':1,'farm_id':2}, {'brand_id':1,'farm_id':3}, {'brand_id':2,'farm_id':4} ] function multisort(array, ...compairers) { return array.sort((a, b) => { for (const c of compai
#include <iostream> #include <cassert> using namespace std; ; char a[max_len]; void topK(int n, int m, int& k, int i) { || i >= m) return; ; j < ; j++) { a[i] = j + '; a[i+] = '\0'; int v = atoi(a); && v <= n && k