[题解]Making The Grade(DP+结论) VJ:Making the Grade HNOI-D2-T3 原题,禁赛三年. 或许是我做过的最简单的DP题了吧(一遍过是什么东西) 之前做过关于绝对值的题目,这种要求绝对值最小的题目,有一个很普遍的结论,最优解的集合中,一定有一个满足所有元素一定是所给定的元素中的元素,具体证明或许就是把括号拆开或者反证法吧. 然后就是这种看起来是\(O(n^3)\)的DP可以通过巧妙的实现降到\(O(n^2)\),当然你暴力使用数据结构变成\(O(n^2

Description A straight dirt road connects two fields on FJ's farm, but it changes elevation more than FJ would like. His cows do not mind climbing up or down a single slope, but they are not fond of an alternating succession of hills and valleys. FJ

Description A straight dirt road connects two fields on FJ's farm, but it changes elevation more than FJ would like. His cows do not mind climbing up or down a single slope, but they are not fond of an alternating succession of hills and valleys. FJ

C. Efim and Strange Grade time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Efim just received his grade for the last test. He studies in a special school and his grade can be equal to any po

Making the Grade Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6445   Accepted: 2994 Description A straight dirt road connects two fields on FJ's farm, but it changes elevation more than FJ would like. His cows do not mind climbing up

15.7 Imagine a simple database storing information for students' grades. Design what this database might look like and provide a SQL query to return a list of the honor roll students (top 10%), sorted by their grade point average. 在一个简化的数据库中我们有三个表,St

It all started the summer before second grade when our moving van pulled into herneighborhood It all started (in) the summer before second grade when our moving van pulled into herneighborhood 省略了 in  语法也是根据语言习惯自己总结的东西是语言创造语法[小学]阿康(353636164)  18:58:

Altera的-6.-7.-8速度等级逆向排序,Xilinx速度等级正向排序. 不很严密地说,“序号越低,速度等级越高”这是Altera FPGA的排序方法, “序号越高,速度等级也越高”这是Xilinx FPGA的排序方法. 从那时起,就一直没搞明白speed grade是怎么来的,唯一的概念是:同一款芯片可以有多个速度等级,不同的速度等级代表着不同的性能,不同的性能又导致芯片价格的巨大差异.脑子里总有 一个模模糊糊的推测:FPGA厂家为了提高利润,专门给同一款芯片生产了不同的速度等级. 直到

Description 题目描述 Ted is a employee of Always Cook Mushroom (ACM). His boss Matt gives him a pack of mushrooms and ask him to grade each mushroom according to its weight. Suppose the weight of a mushroom is w, then it’s grade s is s = 10000 - (100 - w

Grade Time Limit: 3000/1500 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 109    Accepted Submission(s): 63 Problem Description Ted is a employee of Always Cook Mushroom (ACM). His boss Matt gives him a pack of m

Making the Grade Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 4656   Accepted: 2206 Description A straight dirt road connects two fields on FJ's farm, but it changes elevation more than FJ would like. His cows do not mind climbing up

解题思路:这题最关键的是要读懂题意,If not all the value are the same but the frequencies of them are the same, there is no mode.这句话是至关重要 的一句.意思是:如果不是所有的值是相同的,并且他们的出现次数是相同的,那么就没有模型.如,1 1 2 2 3 3 ,它们并不是所有的数都是相同的的, 并且1出现2次,2出现2次,3出现2次,所以这组数据是没有模型的,同理,1 2 3 4 5 也是没有模型的,输

http://acm.hdu.edu.cn/showproblem.php?pid=1084 What Is Your Grade? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9580    Accepted Submission(s): 2940 Problem Description “Point, point, life of

1 缘起 以小米盒子为代表的OTT机顶盒.智能电视的快速普及,快速推动了Android技术在机顶盒.智能电视领域的普及.既然都是用的Android操作系统,那么从技术上来说应该是大同小异的,当然和手机APP的应用相比,电视端的APP开发应该有一些都有的特点需要关注,我相信这样的特点应该不会太多. 写这个笔记的缘起在于一个生活上的小小不便,因为儿子正在读小学,每天早上起来都需要听英语,学校发的磁带真的是不方便,老的磁带机相信很少有人用了,虽然也给他买了一个步步高的复读机,不过没用几天就被搁置了.于

Description A straight dirt road connects two fields on FJ's farm, but it changes elevation more than FJ would like. His cows do not mind climbing up or down a single slope, but they are not fond of an alternating succession of hills and valleys. FJ

What Is Your Grade? Problem Description “Point, point, life of student!” This is a ballad(歌谣)well known in colleges, and you must care about your score in this exam too. How many points can you get? Now, I told you the rules which are used in this co

What Is Your Grade? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 9935    Accepted Submission(s): 3041 Problem Description “Point, point, life of student!” This is a ballad(歌谣)well known in c

最优的做法最后路面的高度一定是原来某一路面的高度. dp(x, t) = min{ dp(x - 1, k) } + | H[x] - h(t) | ( 1 <= k <= t ) 表示前 i 个路面单调不递减, 第 x 个路面修整为原来的第 t 高的高度. 时间复杂度O( n³ ). 令g(x, t) = min{ dp(x, k) } (1 <= k <= t), 则转移O(1), g() 只需在dp过程中O(1)递推即可, 总时间复杂度为O( n² ) 然后单调不递增也跑一遍

Description A straight dirt road connects two fields on FJ's farm, but it changes elevation more than FJ would like. His cows do not mind climbing up or down a single slope, but they are not fond of an alternating succession of hills and valleys. FJ

Efim and Strange Grade time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Efim just received his grade for the last test. He studies in a special school and his grade can be equal to any posit

1592: [Usaco2008 Feb]Making the Grade 路面修整 Time Limit: 10 Sec  Memory Limit: 162 MBSubmit: 428  Solved: 316[Submit][Status][Discuss] Description FJ打算好好修一下农场中某条凹凸不平的土路.按奶牛们的要求,修好后的路面高度应当单调上升或单调下降,也就是说,高度上升与高度下降的路段不能同时出现在修好的路中. 整条路被分成了N段,N个整数A_1, ... ,