public static void main(String[] args){ List<Map<String,Object>> list1 = new ArrayList<Map<String,Object>>(); Map<String,Object> map1 = new HashMap<String,Object>(); Map<String,Object> map2 = new HashMap<String

package com.codyy.sso.controller.yuanqu; import java.util.ArrayList; import java.util.HashMap; import java.util.List; import java.util.Map; public class Test { public static void main(String[] args) { List<Map<String, Object>> listMaps = new A

前言 今天看群里小伙伴问了一个非常有意思的问题: 使用 Map<String,Object> 对象接收前端传递的参数,在后端取参时,因为接口文档中明确该字段类型为 Long ,所以对接收的参数进行了强转,即 (Long)参数 ,但是却发生了类型转换异常,报错信息如下: class java.lang.Integer cannot be cast to class java.lang.Long (java.lang.Integer and java.lang.Long are in module

1.List<Map<String,String>>的遍历: Map<String,String> map = new HashMap<String, String>(); map.put("1", "fds"); map.put("2", "valu"); List<Map<String, String>> list = new ArrayList<

今天在查询出的sql中,出现了部门名称和部门ID有重合的数据!当然这样在页面上展示也会容易一起误导!查询出的数据结构如下图 希望根据deptid中 >最后一个节点id把deptname 合并成>最后一个节点名称并且origincode 数量合并,现在贴代码,做个记录: List<Map> dataList = bigScreenService.queryEventOrginCodeNum(); List<Map<String, Object>> result

// public static void main(String[] args) {// List<Map<String, String>> list2 = new ArrayList<Map<String,String>>();// List<Map<String, String>> list3 = new ArrayList<Map<String,String>>();// Map<String,

分页查询 String sql = "返回所有符合条件记录的待分页SQL语句"; int start = (page - 1) * limit + 1; int end = page * limit; sql = "select * from (select fulltable.*, ROWNUM RN from (" + sql + ") fulltable where ROWNUM <= " + end + ") where

java中 Iterator it=wordsmap.entrySet().iterator(); while(it.hasNext()) { Map.Entry<String,Integer> myentry=(Map.Entry<String,Integer>)it.next(); Object mykey=myentry.getKey(); }

1:list<Object[]>的排序   public static void main(String[] args) { // TODO Auto-generated method stub Object[] o1=new Object[4]; o1[0]="5"; o1[1]="o1"; o1[2]="o11"; o1[3]="o111"; Object[] o2=new Object[4]; o2[0]=&

Crazy Search Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3035    Accepted Submission(s): 1133     Problem Description Many people like to solve hard puzzles some of which may lead them to

package JavaTest.test; import java.util.ArrayList; import java.util.HashMap; import java.util.List; import java.util.Map;import java.util.Map.Entry; import java.util.TreeMap; import org.junit.Test; public class JavaBase { //@Test public void stringTe

List<Map<String, Object>> postlist //一个list里面装着多个map,如下 [ {A=0100, B=4}, {A=0200, B=3}, {A=0300, B=2} ] for(int i = 0 ; i < postlist.size() ; i ++){ System.out.println(postlist.get(i).get("A")); //循环打印list里面map键为"A"的值,类型

方法compareTo()比较此对象与指定对象的顺序.如果该对象小于.等于或大于指定对象,则分别返回负整数.零或正整数.返回整数,1,-1,0:返回1表示大于,返回-1表示小于,返回0表示相等. 普通的Integer 类型key进行比较: public class java_ListMapSort { public static void main(String[] args) { List<Map<String, Object>> list = new ArrayList<

一.为什么要实现javaBean与Map<String,Object>相互转换 Spring中的BaseCommandController对象可以将传递过来的参数封装到一个JavaBean对象中去,而不需要我们再频繁使用request.getParameter()方法,再像bean去设置属性了,从而简化了开发工作.BeanUtils.populate方法将request提交的页面表单自动填写到你创建的对象中去. 二.如何实现javabean与Map<String,Object>之间

Shuffle'm Up Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 14471 Accepted: 6633 Description A common pastime for poker players at a poker table is to shuffle stacks of chips. Shuffling chips is performed by starting with two stacks of po

js怎样给input对象追加属性,如disabled $(":textbox").attr({"disabled":true}); List<Map<String,Object>>遍历: List<Map<String,Object>> strLists = new ArrayList<Map<String,Object>>(); if(strLists!=null){ if(strLists.

我模仿lucene的BytesRef写了一个CharsRefIntHashMap,实測效果并不如HashMap<String, Integer>.代码例如以下: package com.dp.arts.lucenex.utils; import org.apache.lucene.util.CharsRef; public interface CharsRefIntMap { public static abstract class CharsRefIntEntryAccessor { pub

一.JSON数据格式 1.1.常用JSON数据格式 1.对象方式:JSONObject的数据是用 { } 来表示的, 例如: { "id" : "123", "courseID" : "huangt-test", "title" : "提交作业", "content" : null } 2.数组方式:JSONArray,顾名思义是由JSONObject构成的数组,用

@RequestMapping(value = "/getBaseCodess", method = RequestMethod.GET) public ModelAndView getBaseCodess(HttpServletRequest request, HttpServletResponse response) { List<Map<String,Object>> depts = new ArrayList<>(); try { Integ