Problem Description A frog has just learned some number theory, and can't wait to show his ability to his girlfriend. Now the frog ,,⋯ from the bottom, so are the columns. At first the frog is sitting at grid (sx,sy), and begins his journey. To show
今天推导公式,发现居然有对矩阵的求导,狂汗--完全不会.不过还好网上有人总结了.吼吼,赶紧搬过来收藏备份. 基本公式:Y = A * X --> DY/DX = A'Y = X * A --> DY/DX = AY = A' * X * B --> DY/DX = A * B'Y = A' * X' * B --> DY/DX = B * A' 1. 矩阵Y对标量x求导: 相当于每个元素求导数后转置一下,注意M×N矩阵求导后变成N×M了 Y = [y(ij)] --> dY/
Toxophily Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1429 Accepted Submission(s): 739 Problem Description The recreation center of WHU ACM Team has indoor billiards, Ping Pang, chess an
Problem Description One day, Y_UME got an integer N and an interesting program which is shown below: Y_UME wants to play with this program. Firstly, he randomly generates an integer n∈[1,N] in equal probability. And then he randomly generates a permu