http://c.biancheng.net/cpp/html/792.html C语言提供了几个标准库函数,可以将任意类型(整型.长整型.浮点型等)的数字转换为字符串. 以下是用itoa()函数将整数转换为字符串的一个例子: # include <stdio.h> # include <stdlib.h> void main (void) { int num = 100; char str[25]; itoa(num, str, 10); printf("The num
readdir函数: struct dirent *readdir(DIR *dirp); The data returned by readdir() may be overwritten by subsequent calls to readdir() for the same directory stream. 成功时,readdir() 返回指向 dirent 结构的指针.(这个结构是静态分配的:不要试图去free(3) 它.)如果到达了上当结尾,NULL 被返回并保持ERRNO不变
问题: 设计一函数,求整数区间[a,b]和[c,d]的交集.(c/c++.Java.Javascript.C#.Python) 1.Python: def calcMixed(a,b,c,d): rtn=[] list1=range(a,b+1) for num in range(c,d+1): if num in list1: rtn.append(num) return rtn mixed=calcMixed(1,8,5,9) print(mixed) 2.
参考这篇文章的代码封装了一个类似Matlab中的magic函数,用来生成魔方矩阵. #!/usr/bin/env python # -*- coding: utf-8 -*- import numpy as np def magic(n): row,col=0,n//2 magic=[] for i in range(n): magic.append([0]*n) magic[row][col]=1 for i in range(2,n*n+1): r,l=(row-1+n)%n,(col+1)