matlab中有专门的solve函数来解决方程组的(a-x)^2+(b-y)^2=e^2(C-x)^2+(D-y)^2=v^2已知a,b,c,d,e,v 值求解 X,Y 请问用 matlab 如何写,就是求2个园的交点问题.仿真程序为:global a b c d e v;>> a=1;b=0;c=-1;d=0;e=1.5;v=1.5;%设定你这几个未知数的值>> syms x y;%%%%%%x,y是变量>> [x,y]=solve('x^2+y^2-2*a*x-2*
Description Last September, Hangzhou raised the taxi fares. The original flag-down fare in Hangzhou was 10 yuan, plusing 2 yuan per kilometer after the first 3km and 3 yuan per kilometer after 10km. The waiting fee was 2 yuan per five minutes. Passen
1.安装matplotlib pip3 install matplotlib sudo apt install python3-tk 2.分段函数 from pylab import * x = linspace(0,8,200) cond = [True if (i > 2 and i < 5) else False for i in x] y = sin(x)*(x<2)+cos(x)*cond + x*(x>5) plot(x,y),show() 3.
更新:x1,y1,x2,y2不用long long 会wa.. #include<iostream> #include<cstring> #include<cstdio> #include<algorithm> using namespace std; #define maxn 200005 #define lson l,m,rt<<1 #define rson m+1,r,rt<<1|1 #define ll long long l
1.绘制分段函数:y=4sin(4πt)-sgn(t-0.3)-sgn(0.72-t) import numpy as npimport matplotlib.pyplot as plt#绘制分段函数:y=4sin(4πt)-sgn(t-0.3)-sgn(0.72-t) def sgn(x): if x > 0: return 1 elif x < 0: return -1 else: return 0 t = np.arange(0, 1, 0.01)y = []for i in t: y_