mysql 存储过程:提供查询语句并返回查询执行影响的行数DELIMITER $$ DROP PROCEDURE IF EXISTS `p_get_select_row_number`$$ CREATE ), OUT p_count ) ) BEGIN -- 声明 ; ); -- 赋值 SET @stmt = CONCAT(p_select_sql); -- prepare PREPARE s1 FROM @stmt; -- 执行 EXECUTE s1; -- 获取查询影响的行数 SET @cn
原文:sqlserver查询所有表的行数的sql语句 select object_name(id),rowcnt from sysindexes where indid<2 and objectproperty(id,'ismsshipped')=0 order by rowcnt desc select a.name, b.rows from sysobjects a inner join sysindexes b on a.id = b.id where a.type = 'u' and b
Super Mario Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3625 Accepted Submission(s): 1660 Problem Description Mario is world-famous plumber. His “burly” figure and amazing jumping ability
db.users.find() select * from users db.users.find({"age" : 27}) select * from users where age = 27 db.users.find({"username" : "joe", "age" : 27}) select * from users where "username" = "joe" and
有这样一个题,用一条SQL语句 查询出每门课都大于80分的学生姓名. 下面是表 分析,查询每门课程都大于80的学生.SELECT DISTINCT name FROM dbo.student WHERE fenshu<=80查询出来的结果是李四王五张三都有. 小于等于80的语句SELECT name FROM dbo.student WHERE fenshu<=80 只有张三一个. 这个是重复的,值得利用,用not in(不在次语句中的)语句将两句拼写到一块如下: SELECT DISTINC