SELECT DATE_FORMAT(releaseDate,"%Y年%m月") AS dates,COUNT(*) FROM t_diary GROUP BY DATE_FORMAT(releaseDate,"%Y年%m月") ORDER BY DATE_FORMAT(releaseDate,"%Y年%m月") DESC ;releaseDate 日期 t_diary表名 DATE_FORMAT();按照格式对某个日期操作ORDER BY 排序
1.简单的,按月统计数量 SELECT CREATE_DATE, DATE_FORMAT(CREATE_DATE, '%Y-%m') AS month , COUNT(*) AS sum FROM pt_user GROUP BY month; 2.按月累加统计数据 SELECT a.month, SUM(b.total) AS total FROM ( SELECT DATE_FORMAT(CREATE_DATE, '%Y-%m') AS month, SUM(sum) AS total FR
CREATE TABLE emp(id INT PRIMARY KEY,NAME VARCHAR(11),dep_id INT ,salary INT); CREATE TABLE dept(id INT PRIMARY KEY,NAME VARCHAR(11),parentid INT); 获取各部门人数信息: SELECT e.dep_id,d.name,COUNT(e.dep_id) FROM emp e,dept d WHERE e.dep_id=d.id GROUP BY e.dep_
按年汇总,统计: select sum(mymoney) as totalmoney, count(*) as sheets from mytable group by date_format(col, '%Y'); 按月汇总,统计: select sum(mymoney) as totalmoney, count(*) as sheets from mytable group by date_format(col, '%Y-%m'); 按季度汇总,统计: select sum(mymone
select p.id comperitorId,p.compcorp competitorName, sum(case when c.kindname = 'ATM' then c.num else 0 end) atm, sum(case when c.kindname = 'CRS' then c.num else 0 end) crs, sum(case when c.kindname = 'VTM' then c.num else 0 end) vtm, sum(case when c
在mysql数据库中,常常会遇到统计当天的内容.例如,在user表中,日期字段为:log_time统计当天 sql语句为: select * from user where date(log_time) = curdate(); curdate()表示当天日期统计前一天 如果表示前一天的数据,则不能使用curdate()-1,因为当日期为月初时,curdate()-1 日期就不是上一个月的月末日期. 例如:今天是6月1日,理论上curdate()-1为5月31日,但是curdate()-1得到不