第一种方案 DAO层的函数方法 public User selectUser(String name,String area); 对应的Mapper.xml <select id="selectUser" resultMap="BaseResultMap"> select * from user_user_t where user_name = #{0} and user_area=#{1} </select> 其中,#{0}代表接收的是da
一.单个参数: public List<XXBean> getXXBeanList(String xxCode); <select id="getXXXBeanList" parameterType="java.lang.String" resultType="XXBean"> select t.* from tableName t where t.id= #{id} </select> 其中方法名和ID一致,
一.单个参数: public List<XXBean> getXXBeanList(String xxCode); <select id="getXXXBeanList" parameterType="java.lang.String" resultType="XXBean"> select t.* from tableName t where t.id= #{id} </select> 其中方法名和ID一致,
原文地址:https://www.cnblogs.com/mingyue1818/p/3714162.html 一.单个参数: public List<XXBean> getXXBeanList(String xxCode); <select id="getXXXBeanList" parameterType="java.lang.String" resultType="XXBean"> select t.* from t
一.单个参数: public List<XXBean> getXXBeanList(@param("id")String id); <select id="getXXXBeanList" parameterType="java.lang.String" resultType="XXBean"> select t.* from tableName t where t.id= #{id} </sele
一.单个参数: public List<XXBean> getXXBeanList(String xxCode); <select id="getXXXBeanList" parameterType="java.lang.String" resultType="XXBean"> select t.* from tableName t where t.id= #{id} </select> 其中方法名和ID一致,
一.单个参数: public List<XXBean> getXXBeanList(String xxCode); <select id="getXXXBeanList" parameterType="java.lang.String" resultType="XXBean"> select t.* from tableName t where t.id= #{id} </select> 其中方法名和ID一致,