oracle 实现多字段匹配一个关键字查询语句:有两种方法(经测试,10g中不能用,11g才行): 第一种. select * from table where ('字段名1' ||'字段名2' ||...) like "%keyValue%"; 第二种:(1)如果是两个字段的话:select * from table where concat(字段名1,字段名2) like "%keyValue%";(2)如果是多个字段的话:select * from table
function RndNum(n) { var rnd = ""; for (var i = 0; i < n; i++) rnd += Math.floor(Math.random() * 10); return rnd; } function start(tip) { let maxCount = RndNum(3); let ary = []; let match = 0; let eachCount = 0; console.group(tip); eachAry(ar
现在有这么一个需求 一个questions表,字段有题目(TestSubject),选项(AnswerA,AnswerB,AnswerC,AnswerD,AnswerE) 要求字段不包含png,jpg,jpeg,gif 正常情况下会这么写 select * from questions where TestSubject not like '%png%' or TestSubject not like '%png%' or ...... 总共需要写6 * 4 = 24个. 第一步优化,将字段拼接
错误示范: var projectSubmitInfos = (from project in db.T_PM_Project join member in db.T_PM_Member on project.ProjectID equals member.ProjectID join user in db.T_Sys_UserInfo on member.UserID equals user.UserID join task in taskSummary on new {member.User