select gr,num,dt,(select bys from test where gr=b.gr and dt=b.dt) bys from ( select gr,count(0) num,max(dt) dt from test group by gr ) b //如果有重复项,可用如下语句(针对Mysql的limit,Oracle 可用 rownum<2) select gr,num,dt,(select bys from test where gr=b.gr and dt=b.d
场景:sql server 2008 drop table ID CREATE TABLE ID ( id ,) not null, code int , D date, PRIMARY KEY (id) ) ,getdate()) ,getdate()) ,getdate()) ,getdate()) ,'2017-08-02') ,'2017-08-01') select * from ID 目标: select COUNT(*) from ID group by code 产生code列唯
获取分组后取某字段最大一条记录 方法一:(效率最高) select * from test as a where typeindex = (select max(b.typeindex) from test as b where a.type = b.type ); 方法二:(效率次之) select a.* from test a, (select type,max(typeindex) typeindex from test group by type) b where a.type = b
/****** Object: StoredProcedure [dbo].[getSplitValue] Script Date: 03/13/2014 13:58:12 ******/ SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO ALTER PROCEDURE [dbo].[getSplitValue] AS --定义获取GUID ) SET @NEWID= REPLACE(NEWID(),'-','') --判断临时表数据是否存在,如果
例如student表: studentID studentName studentScore 01 Alice 90 02 Bill 95 03 Cindy 100 一.拼接多个字段的值 select studentID+‘-’+studentName+'-'+studentScore AS studentInfo from student 结果: 二.一个字段多条记录的拼接 select stuff((select '|'+studentName from student for xm
如student表: studentID studentName studentScore 01 Alice 90 02 Bill 95 03 Cindy 100 一.拼接多个字段的值 select studentID+‘-’+studentName+'-'+studentScore AS studentInfo from student 结果: 二.一个字段多条记录的拼接 select stuff((select '|'+studentName from student for xml p
分组后,统计记录条数: SELECT num,count(*) AS counts from test_a GROUP BY num; 查询结果如下: 对num去重后的数量的统计: SELECT count(t.counts) FROM ( SELECT num,count(*) AS counts from test_a GROUP BY num ) AS t; SELECT count(DISTINCT num) AS count FROM test_a; 它俩结果一样,都是5:只是一个是子