如果ID是主键或者有索引,可以直接查找: 方法一: 查询上一条记录的SQL语句(如果有其他的查询条件记得加上other_conditions以免出现不必要的错误): select * from table_a where id = (select id from table_a where id < {$id} [and other_conditions] order by id desc limit 1
如果ID是主键或者有索引,可以直接查找: 方法一: 查询上一条记录的SQL语句(如果有其他的查询条件记得加上other_conditions以免出现不必要的错误): select * from table_a where id = (select id from table_a where id < {$id} [and other_conditions] order by id desc limit 1) [and other_conditions]; 查询下一条记录的SQL语句(如果有其他的
上一条记录的SQL语句: * from news where newsid<id order by newsid DESC 下一条记录的SQL语句: * from news where newsid>id order by newsid ASC 开发中遇到需要在当前页面显示当前文章的上一篇文章和下一篇文章,百度了一下,搜索到以上SQL语句:
1 引言 当更新字段缺少where语句时,mysql会提示一下错误代码: Error Code: 1175. You are using safe update mode and you tried to update a table without a WHERE that uses a KEY column To disable safe mode, toggle the option in Preferences -> SQL Queries and reconnect. 0.000 se
在项目中要查询用户最近登录的一条记录的 ip 直接写如下 SQL: SELECT ip,MAX(act_time) FROM users_login GROUP BY login_id; 但是这样是取不出用户登录记录中时间最大的那个 ip , 仅仅只是查到了最大时间,和 ip 没关系 找了相当多的文章,经过自己测试,发现一个比较好的方式处理这个问题,举例如下: 现在假设有一张数据表 A , 字段和数据如下: 姓名(name) 身份证(唯一标识)(id) 购买产品(pro) 价格(price) 数
上图数据:SNum为”18004XXXXX000001K2GW 4000 L1C“,OffLineStation为“OP1010”的有两条数据,当where条件中为上述两者时会同时更新这两条数据,并不是我想要的. 更新要求:在上述条件下更新最新的一条记录 Id from RM_RepairOffLine where SNum = '18004XXXXX000001K2GW 4000 L1C' and OffLineStation = 'OP1010' order by CreationTime
删除重复数据保留name中id最小的记录 delete from order_info where id not in (select id from (select min(id) as id from order_info group by order_number) as b); delete from table where id not in (select min(id) from table group by name having count(name)>1) and id i
一.对分组的记录取前N条记录:例子:取前 2条最大(小)的记录 .用子查询: SELECT * FROM right2 a WHERE > (SELECT COUNT(*) FROM right2 b WHERE b.id=a.id AND b.account>a.account) ORDER BY a.id,a.account DESC .用exists半连接: SELECT * FROM right2 a WHERE EXISTS (SELECT COUNT(*) FROM right2