最近一个月 SELECT * FROM table WHERE DATE_SUB(CURDATE(), INTERVAL 1 MONTH) <= date(time); 本月.当前月 SELECT * FROM table WHERE DATE_FORMAT(o.createTime,'%Y-%m') = DATE_FORMAT(CURDATE(),'%Y-%m'); 上个月 SELECT * FROM table WHERE PERIOD_DIFF(DATE_FORMAT(NOW(),'%Y-
NthDayOfWeek 计算并返回指定日期是该月第几周 Unit:DateUtils function NthDayOfWeek(const AValue: TDateTime): Word; Example: Uses SysUtils,DateUtils; Begin Write('Today is the ',NthDayOfWeek(Today),'-th '); Writeln(formatdateTime('dddd',Today),' of the month.');En
from :http://www.cnblogs.com/aeiou/p/5719396.html http://www.cnblogs.com/zengguowang/p/5541431.html mysql计算排名,获取行号rowno 学生成绩表数据 SELECT * FROM table_score ORDER BY score DESC; 获取某个学生成绩排名并计算该学生和上一名学生成绩差,是并列排名 SELECT *, (SELECT count(DISTINCT score) FRO
mysql计算排名,获取行号rowno 学生成绩表数据 SELECT * FROM table_score ORDER BY score DESC; 获取某个学生成绩排名并计算该学生和上一名学生成绩差,是并列排名 SELECT *, ( AS rank, #获取排名,并列 (); #获取学生周一的成绩排名和与上一名的成绩差 获取所有学生成绩排名-并列排名 SELECT *, ( AS rank #获取排名-并列 FROM table_score AS a ORDER BY rank; #获取学生
题目4: 巧妙利用SimpleDateFormat根据各种信息求日期.2008-11月第6周的星期日是几号? import java.text.ParseException;import java.text.SimpleDateFormat;import java.util.*;public class Test { public static void main(String[] args) { SimpleDateFormat formatter2 = new Simpl
转自:http://www.cnblogs.com/likwo/archive/2010/04/16/1713282.html 查询一天: select * from table where to_days(column_time) = to_days(now());select * from table where date(column_time) = curdate(); 查询一周: select * from table where DATE_SUB(CURDATE(), INTER
(转载)http://www.cnblogs.com/likwo/archive/2010/04/16/1713282.html 查询一天: select * from table where to_days(column_time) = to_days(now());select * from table where date(column_time) = curdate(); 查询一周: select * from table where DATE_SUB(CURDATE(), INTE