检查重复记录 -- 检查重复code1 select count(identity) num, identity from event_log where code='code1' order by num desc 删除重复记录 DELETE FROM event_log WHERE `code`='code1' AND identity IN ( SELECT identity from ( ) a ) AND id NOT IN ( SELECT keepId FROM ( ) b ) 其
需求:删除station_id.ab_data_time.item_code_id.data_cycle.ab_value 字段重复的记录 #查询重复的数据 select b.id,b.station_id,b.ab_data_time,b.item_code_id,b.data_cycle,b.ab_lable,b.ab_value from d_abnormal_data_yyyymms b where (b.station_id,b.ab_data_time,b.item_code_id,
1. 查询需要删除的记录,会保留一条记录. select a.id,a.subject,a.RECEIVER from test1 a left join (select c.subject,c.RECEIVER ,max(c.id) as bid from test1 c where status=0 GROUP BY RECEIVER,SUBJECT having count(1) >1) b on a.id< b.bid where a.subject=b.subject and a.R
语句: delete from table1 where id not in (select minid from (select min(id) as minid from table1 group by field1) b); 翻译成中文就是: 删除,“table1”中,id 不在此范围的所有记录.此范围是,筛选出,以field1分组的,所有组别中id的最小的一个. 更直接点就是,以field1分组,选出分组中id最小的一条记录,然后剩下的全部删除. 理解不正确的话,请指点一二.
删除表中重复记录,只保留一条: delete from 表名 where 字段ID in (select * from (select max(字段ID) from 表名 group by 重复的字段 having count(重复的字段) > 1) as b); 实例: 2.当想要为某一个表建立一个唯一索引,由于表中有重复记录而无法进行时,需要删除重复记录. 例表 dept id_no id_name 100 'AAA' 101 'BBB' 102 'CCC' 103 'DDD' 100 'E
1在日常使用mysql中 前端页面点击次数过多 mysql就会容易产生冗余数据,那这些数据该怎么删除呢 说下思路 查询重复字段id 查询重复字段最小id 删除重复字段ID 保留最小ID 查询重复记录这没的说 SELECT 重复记录字段 from 表 GROUP BY 重复记录字段 HAVING COUNT(*)>1 查询重复字段ID 例如 SELECT id FROM way_bills WHERE source_goods_id in (SELECT source_goods_id from
mysql 删除单表内多个字段重复的数据 DELETE from lot_log_payflow WHERE (pay_no,sub_flow_type) in () s1) AND id ) s2); 查询重复的数据 select * from lot_log_payflow WHERE (pay_no,sub_flow_type) in () s1) AND id ) s2) order by create_time asc; 删除单个字段重复数据 DELETE from lot_order
INSERT INTO hk_test(username, passwd) VALUES ('qmf1', 'qmf1'),('qmf2', 'qmf11') delete from hk_test where username='qmf1' and passwd='qmf1' MySQL里查询表里的重复数据记录: 先查看重复的原始数据: 场景一:列出username字段有重读的数据 select username,count(*) as count from hk_test group by
delete from 表名 where id not in (select d.id from (SELECT id FROM 表名 GROUP BY c1,c2,c3,c4)as d) #去重复,把url重复,且区为空的中去掉.select * from TABLE where url in (select u.url from (select * from TABLE where id not in (select d.id from (SELECT id FROM TABLE GROUP
先上一个基础的: var a = [1,2,3,3,4]; var b = []; for (var i = 0; i < a.length; ++i) { if (b.indexOf(a[i]) == -1) { b.push(a[i]); } } console.log(b);//[1,2,3] 有两种方法,第一种是出现重复则删除: var arr = [{ "Type": "第一种型号", "ERP": 5033701, "
鉴于项目的需要,就从网上找到该文章,文章分析得很详细也很易懂,在android里, (不知道是不是现在水平的限制,总之我还没找到在用ContentProvider时可以使用子查询),主要方法是用SQLiteDatabase 的 rawQuery,直接运行sql语句就可以了. 以下是转自网上的一篇文章 本文就和大家一起深入研究下mysql中group by与order by.下面是我模拟我的内容表 我现在需要取出每个分类中最新的内容 select * from test group by cate
203题是在链表中删除一个固定的值,83题是在链表中删除重复的数值,但要保留一个:82也是删除重复的数值,但重复的都删除,不保留. 比如[1.2.2.3],83题要求的结果是[1.2.3],82题要求的结果是[1,3]. 这种题用递归去做比较方便思考,特别是这种重复的数值.递归就是只遍历当前的节点的情况,之前的不用管,之后的以当前节点为出发点思考问题. 203. Remove Linked List Elements class Solution { public: ListNode* remo