mysql 按年.月.周.日分组查询 1.按照年份分组查询 SELECT DATE_FORMAT(t.bill_time,'%Y') month_time,sum(t.pay_price) total FROM f_bill t GROUP BY month_time; 查询结果 2.按照月份分组查询 SELECT DATE_FORMAT(t.bill_time,'%Y-%m') month_time,sum(t.pay_price) total FROM f_bill t GROUP BY m
HAVING 筛选后再 筛选 SELECT CLASS,SUM(TOTAL_SCORES) FROM student_score GROUP BY CLASS HAVING SUM(TOTAL_SCORES)>; 这里用where SUM(TOTAL_SCORES)>505的话,将会出错,因为表中根本没有总成绩分数这项,这是分组之后才有的 ELECT CLASS,SNAME,TOTAL_SCORES FROM student_score WHERE TOTAL_SCORES>250 GR
表TESTER 字段:id -- INT date -- TIMESTAMP 1.如何按年.月.日分组查询? select DATE_FORMAT(date,'%Y-%m-%d') time, count(*) count from TESTER group by year(date), month(date), day(date); 其中year().month().day()分别是提取date中的年.月.日字段. 2.时间分组查询的效率? 在不建立索引时,我100W行数据进行测试,用
MySQL按时间统计每个小时记录数 方案1: ? 1 2 3 4 5 6 7 SELECT @rownum := @rownum + 1 AS ID, CONCAT((CASE WHEN t.hour = 24 THEN 0 ELSE t.hour END),':00:00') AS TIME, COUNT(*) AS COUNT FROM (SELECT id, HOUR(DATE_FORMAT(createtime,'%H:%i:%s'))+1 AS HOUR FROM b
Mysql按时间段分组查询来统计会员的个数,mysql个数 Mysql按时间段分组查询来统计会员的个数,mysql个数 1.使用case when方法(不建议使用)- 代码如下 复制代码SELECT COUNT(DISTINCT user_id) user_count, CASE WHEN create_time>1395046800 AND create_time<1395050400 THEN '17:00-18:00' WHEN create_time>1395050400 AND