转自:http://www.cnblogs.com/likwo/archive/2010/04/16/1713282.html 查询一天: select * from table where to_days(column_time) = to_days(now());select * from table where date(column_time) = curdate(); 查询一周: select * from table   where DATE_SUB(CURDATE(), INTER

//今天 select * from 表名 where to_days(时间字段名) = to_days(now()); //昨天 SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1 //近7天 SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名) //近30天 SELECT * FROM 表名 where DATE_SUB(

sql: AND date_format(createDTM, MONTH),'%Y-%m-%d')

(转载)http://www.cnblogs.com/likwo/archive/2010/04/16/1713282.html 查询一天: select * from table where to_days(column_time) = to_days(now());select * from table where date(column_time) = curdate(); 查询一周: select * from table   where DATE_SUB(CURDATE(), INTE

1.一个月第一天的Select DATEADD(mm, DATEDIFF(mm,0,getdate()), 0) 2.本周的星期一Select DATEADD(wk, DATEDIFF(wk,0,getdate()), 0) 3.一年的第一天Select DATEADD(yy, DATEDIFF(yy,0,getdate()), 0) 4.季度的第一天Select DATEADD(qq, DATEDIFF(qq,0,getdate()), 0) 5.当天的半夜Select DATEADD(dd,

需求:查询最近三个月的每一天的业绩总和 因为最近三个月每个月的天数是不一样,所以不能用这篇文章:Mysql查询最近30天的数据(每天的业绩总和数据) 介绍的用固定多少天去查数据.需要一个新方法. 一.生成每个月的每一天的时间序列 SELECT ADDDATE(y.first, x.d - 1) as d FROM (SELECT 1 AS d UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 U

mysql提供了两个函数: from_unixtime(time_stamp) -> 将时间戳转换为日期 unix_timestamp(date) -> 将指定的日期或者日期字符串转换为时间戳 如果要查询当天的订单的记录: [plain] select count(*) from b_order Where date_format(from_unixtime(create_time),'%Y-%m-%d') = date_format(now(),'%Y-%m-%d') 也可以这样: [pla

需求描述: 在mysql中,查看两个日期之间相差多少天 操作过程: 1.通过datediff函数,查看两个日期之间相差多少天 mysql> select datediff('2018-06-26','2018-06-25'),datediff('2018-06-20','2018-06-26'); +-------------------------------------+-------------------------------------+ | datediff('2018-06-26

数据库日期类型是int类型的,该查询结果是datetime类型的 SELECT from_unixtime( `时间列名` ) FROM 表名 如果原来类型是datetime类型,查询结果要是int类型则 SELECT unix_timestamp( `时间列名` ) FROM 表名

$(function () { getdatepicker(); today(); getPreMonth(); getdatetimepicker(); }); function today(){ $("input[name='applydate']").datepicker('setDate',new Date()); $("input[name='applydate2']").datepicker('setDate',new Date()); }$(docum

$conn = new mysqli(....); $sql = ""; $query = $conn->query($sql); 这里,如果查询正常,有数据返回,那么$query是个对象: 如果查询数据库错误,$query是false: 如果查询没有错误,但是没有查询到任何结果,$query仍然是个对象,$query->num_rows可判断返回记录条数.

select timestampdiff(SECOND,'2011-09-25 23:23:13','2011-09-26 22:23:11'); 其中SECOND同样可以改为HOUR,MINUTE

DELIMITER $$ USE `topsale`$$ DROP PROCEDURE IF EXISTS `sale_proce`$$ CREATE DEFINER=`root`@`%` PROCEDURE `sale_proce`(IN countryList VARCHAR() ,IN beg VARCHAR(),IN endd VARCHAR()) BEGIN DELETE FROM sale_record WHERE country_id IN(countryList) AND dat

select COLUMN_NAME from information_schema.`COLUMNS`        -- 这行不变,照抄 where TABLE_SCHEMA = 'xerp'                     -- 数据库名xerp and TABLE_NAME = 'sdb_ome_orders'                 -- 表名sdb_ome_orders

SELECT COUNT(*) TABLES, table_schema FROM information_schema.TABLES  WHERE table_schema = 'palm_2_0_16' palm_2_0_16就为你所要查的库名

如果你要严格要求是某一年的,那可以这样 查询一天: select * from table where to_days(column_time) = to_days(now()); select * from table where date(column_time) = curdate(); 查询一周: DAY) <= date(column_time); 查询一个月: select * from table where DATE_SUB(CURDATE(), INTERVAL 1 MONTH

查询一天:select * from 表名 where to_days(时间字段名) = to_days(now()); 昨天 SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1 7天 SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名) 查询一周内数据 select * from Tabel名 where 时间字段名 bet

24小时内记录(即86400秒) $sql="SELECT video_id,count(id)as n FROM `rec_down` WHERE UNIX_TIMESTAMP(NOW())-UNIX_TIMESTAMP(add_time)<=86400 group by video_id order by n desc ";$sql="select a.id,a.title,b.n from video_info a,(".$sql.")b wh

本周内:select * from wap_content where week(created_at) = week(now) 查询一天:select * from table where to_days(column_time) = to_days(now());select * from table where date(column_time) = curdate(); 查询7天:select * from table  where DATE_SUB(CURDATE(), INTERVA

本周内:select * from wap_content where week(created_at) = week(now) 查询一天:select * from table where to_days(column_time) = to_days(now());select * from table where date(column_time) = curdate(); 查询7天:select * from table  where DATE_SUB(CURDATE(), INTERVA