一 当数字的精度被定为number(3,2)时, 这时他能输入的数字整数部分只能是3-2=1位, 小数位如果不够会用0补齐, 超出的四舍五入保留3位小数. SQL> insert into t_te(num1) values(45.67882);insert into t_te(num1) values(45.67882)ORA-01438: 值大于为此列指定的允许精度 SQL> insert into t_te(num1) values(12.3);insert into t_te(num1

 nanosleep的精度与调度算法的关系 2011-12-03 13:05:17 分类: LINUX     Heartwork前辈在我前一篇博文多线程条件下的计数器(2)中的回复中提到,   nanosleep的问题很好解释,看这里…… The nanosleep() function shall cause the current thread to be suspended from execution until either the time interval specified b

1666: [Usaco2006 Oct]Another Cow Number Game 奶牛的数字游戏 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 502  Solved: 432[Submit][Status] Description 奶牛们又在玩一种无聊的数字游戏.输得很郁闷的贝茜想请你写个程序来帮她在开局时预测结果.在游戏的开始,每头牛都会得到一个数N(1<=N<=1,000,000).此时奶牛们的分数均为0.如果N是奇数,那么奶牛就会把

Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5]. Note: The order

Given an integer n, count the total number of digit 1 appearing in all non-negative integers less than or equal to n. For example: Given n = 13, Return 6, because digit 1 occurred in the following numbers: 1, 10, 11, 12, 13. Hint: Beware of overflow.

Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 这道题是之前那道 Single Number 单独的数字的延伸,那道题的解法

18.4 Write a method to count the number of 2s between 0 and n. 这道题给了我们一个整数n,让我们求[0,n]区间内所有2出现的个数,比如如果n=20,那么满足题意的是2, 12, 20,那么返回3即可.LeetCode上有一道很类似的题Factorial Trailing Zeroes,但是那道题求5的个数还包括了因子中的5,比如10里面也有5,这是两题的不同之处.那么首先这题可以用brute force来解,我们对区间内的每一个数字

我现在在做一个叫<leetbook>的开源书项目,把解题思路都同步更新到github上了,需要的同学可以去看看 地址:https://github.com/hk029/leetcode 这个是书的地址:https://hk029.gitbooks.io/leetbook/ 009. Palindrome Number[E] 问题: Determine whether an integer is a palindrome. Do this without extra space. 思路 这里说不

题目地址:http://poj.org/problem?id=1019 Number Sequence Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 35680   Accepted: 10287 Description A single positive integer i is given. Write a program to find the digit located in the position i in

A strobogrammatic number is a number that looks the same when rotated 180 degrees (looked at upside down). Write a function to determine if a number is strobogrammatic. The number is represented as a string. For example, the numbers "69", "

Determine whether an integer is a palindrome. Do this without extra space. 题目标签:Math 题目给了我们一个int x, 让我们判断它是不是回文数字. 首先,负数就不是回文数字,因为有个负号. 剩下的都是正数,只要把数字 reverse 一下,和原来的比较,一样就是回文. 当有overflow 的时候,返回一个负数就可以了(因为负数肯定不会和正数相等). Java Solution: Runtime beats 61.

Given a non-empty array of integers, every element appears three times except for one, which appears exactly once. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

https://github.com/dt-fe/number-precision ~(function(root, factory) { if (typeof define === "function" && define.amd) { define([], factory); } else if (typeof module === "object" && module.exports) { module.exports = fa

Determine whether an integer is a palindrome. Do this without extra space. click to show spoilers. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction of using ext

Determine whether an integer is a palindrome. Do this without extra space.(不要使用额外的空间) Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction of using extra space. You

Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example,Given nums = [0, 1, 3] return 2. Note:Your algorithm should run in linear runtime complexity. Could you implement it usi

Description 奶牛们又在玩一种无聊的数字游戏.输得很郁闷的贝茜想请你写个程序来帮她在开局时预测结果.在游戏的开始,每头牛都会得到一个数N(1<=N<=1,000,000).此时奶牛们的分数均为0.如果N是奇数,那么奶牛就会把它乘以3后再加1.如果N是偶数,那么这个数就会被除以2.数字每变动一次,这头奶牛就得到1分.当N的值等于1时,游戏结束,此时的分数就是这头奶牛在这局游戏中的最终得分. 以下是N的初始值为5时,一局游戏的完整过程: N 操作后所得数 注释 总分 5 16 3*5+1

Long Time No See !   题目链接https://leetcode.com/problems/palindrome-number/?tab=Description   首先确定该数字的位数.按照已知数字x对10进行多次求余运算,可以得到数字位数. 具体思路: 1.每次取出该数字的最高位和最低位进行比较. 2.如果不相等则直接返回FALSE, 3.如果相等修改x的值(去掉最高位也同时去掉最低位)其中去掉最高位可以通过求模运算,去掉最低位可以采用除以10 4.进行循环直到x的值不大于

对于一个长度为n+1的数组,其中每一个值的取值范围是[1,n],可以证明的是必然存在一个重复数字(抽屉原理),假设仅存在一个重复数字,找到他. 举例:输入:[1,3,4,2,1],输出:1 自己做的时候,要么时间复杂度到o(n2),要么需要额外的存储空间利用hashset,下面来分析一下leetcode上别人的算法吧. 方法一:通过图论中环的有关知识解决 public int findDuplicate(int[] nums) { // Find the intersection point o

http://www.lydsy.com/JudgeOnline/problem.php?id=1666 这种我就不说了.. #include <cstdio> #include <cstring> #include <cmath> #include <string> #include <iostream> #include <algorithm> using namespace std; #define rep(i, n) for(