Bomb Game Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 806 Accepted Submission(s): 392 Problem Description John and Jack, two mathematicians, created a game called "Bomb Game" at spa
python创建二维 list 的方法是在 list 里存放 list : l = [[1,2,3,4],[5,6,7,8],[9,10,11,12],[13,14,15,16]] numpy可以直接创建一个二维的数组: import numpy as np l = np.array([ [1,2,3,4], [5,6,7,8], [9,10,11,12], [13,14,15,16] ]) numpy二维数组获取某个值: [a, b] : a 表示行索引, b 表示列索引,就是获取第 a 行
1.在http://zxingnet.codeplex.com/网站上下载ZXing .Net的第三方库 2.新建一个WPFproject 3.引入zxing.dll 4.加入引用空间 using ZXing.Common; using ZXing; using ZXing.QrCode; 5.加入引用System.Drawing 6.加入引用空间 using System.Drawing; 7.在xaml中加入一个Image控件,用于显示二维码.命名为image1. 8.编写生成二维码函数:
1.运用composer下载拓展到vendor下 composer require aferrandini/phpqrcode 2.common.php 里面写生成二维码函数 <?php // +---------------------------------------------------------------------- // | ThinkPHP [ WE CAN DO IT JUST THINK ] // +-----------------------------------
虽然numpy数组中有argmax的函数可以获得数组的最大值的索引,但该函数获得的是numpy数组平铺后的索引,也就是一维索引.那么要怎样才能获得二维索引呢?实现很简单,比如我下面的代码: import numpy as np import math a = np.array([[1, 2, 3], [4, 5, 6]]) m, n = a.shape index = int(a.argmax()) x = int(index / n) y = index % n print(x, y) >>