package com.Summer_0420.cn; /** * @author Summer * 获取数值型数组中大于60的元素个数 * 给数值型数组中不足60分的加20分 */ public class TestMethod02 { public static void main(String[] args) { int [] a = {1,35,60,80,75,123,156,32,1}; show(a); } private static void show(int[] a) { i
unsigned int str_num(char *str[], int num[], int len) { int i, j; int count; int flag[len]; ; i < len; i++) { num[i] = ; flag[i] = ; } ; i < len; i ++) { ; j <= len; j ++) { == flag[i])&& ( == strncmp(str[j], str[i], strlen(str[j]) > s
题目描述: Given an integer array with even length, where different numbers in this array represent different kinds of candies. Each number means one candy of the corresponding kind. You need to distribute these candies equally in number to brother and si
题目: Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements. For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0]. Note:
题目:找出一个数组中第m小的值并输出. 代码: #include <stdio.h> int findm_min(int a[], int n, int m) //n代表数组长度,m代表找出第m小的数据 { int left, right, privot, temp; int i, j; left = 0; right = n - 1; while(left < right) { privot = a[m-1]; i = left; j = right; do { while(privo
题目: Given two sorted integer arrays A and B, merge B into A as one sorted array. Note: You may assume that A has enough space to hold additional elements from B. The number of elements initialized in A and B are m and n respectively. 题意要把两个有序的数组合并到他们
