阅读目录: DS01:常用的查找数组中是否有重复元素的三种方法 DS02:常用的JS函数集锦 DS01.常用的查找数组中是否有重复元素的三种方法 1. var ary = new Array("111","22","33","111"); var s = ary.join(",")+","; for(var i=0;i<ary.length;i++) { if(s.replace
Given an array of integers nums sorted in ascending order, find the starting and ending position of a given targetvalue.Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. Ex
题目链接:https://leetcode.com/problems/remove-duplicates-from-sorted-array-ii/#/description 给定一个已经排好序的数组,数组中元素存在重复,如果允许一个元素最多可出现两次,求出剔除重复元素(出现次数是两次以上的)后的数组的长度. For example, Given sorted array nums = [1,1,1,2,2,3], Your function should return length = 5,
题目:给定一个数组array和一个值value,移除掉数组中所有与value值相等的元素,返回新的数组的长度:要求:不能分配额外的数组空间,且必须使用原地排序的思想,空间复杂度O(1); 举例: Given input array nums = [3,2,2,3], val = 3 Your function should return length = 2, with the first two elements of nums being 2. 解题思路: 1. 首先找到第一个等于valu