算法思想 统计二叉树中叶子结点的个数和度为1.度为2的结点个数,因此可以参照二叉树三种遍历算法(先序.中序.后序)中的任何一种去完成,只需将访问操作具体变为判断是否为叶子结点和度为1.度为2的结点及统计操作即可. #include <stdio.h> #include <stdlib.h> int LeafCount=0; int Degree1Count=0; int Degree2Count=0; typedef char DataType; //二叉链表结点的数据类型 typ
#include <iostream> using namespace std; struct Tree { int data; Tree *lchild; Tree *rchild; }tree; Tree *Create(int a1[],int b1[],int n) { int k; ) return NULL; ]; Tree *bt=(Tree *)malloc(sizeof(Tree)); bt->data=root; ;k<n;k++) { if(b1[k]==ro
数据结构实验之二叉树七:叶子问题 Time Limit: 1000MS Memory Limit: 65536KB Submit Statistic Problem Description 已知一个按先序输入的字符序列,如abd,,eg,,,cf,,,(其中,表示空结点).请建立该二叉树并按从上到下从左到右的顺序输出该二叉树的所有叶子结点. Input 输入数据有多行,每一行是一个长度小于50个字符的字符串. Output 按从上到下从左到右的顺序输出二叉树的叶子结点. Example In
Given a binary tree where every node has a unique value, and a target key k, find the value of the nearest leaf node to target k in the tree. Here, nearest to a leaf means the least number of edges travelled on the binary tree to reach any leaf of th
Given a non-empty special binary tree consisting of nodes with the non-negative value, where each node in this tree has exactly two or zero sub-node. If the node has two sub-nodes, then this node's value is the smaller value among its two sub-nodes.
一,问题描述 构建一棵二叉树(不一定是二叉查找树),求出该二叉树中第K层中的结点个数(根结点为第0层) 二,二叉树的构建 定义一个BinaryTree类来表示二叉树,二叉树BinaryTree 又是由各个结点组成的,因此需要定义一个结点类BinaryNode,BinaryNode作为BinaryTree的内部类. 此外,在BinaryTree中需要一定一个BinaryNode属性来表示树的根结点. public class BinaryTree<T extends Comparable<? s
