Base64 报错 的解决办法, 报错如下:1. FormatException: The input is not a valid Base-64 string as it contains a non-base 64 character, more than two padding characters, or a non-white space character among the padding characters. ] System.Convert.FromBase64Str
今天用file_put_content($fileName,$data)产生错误:内容如下: Warning: file_put_contents(images/7d5636992a7395f91744747ffa0ecf0b.gif?b=bgif): failed to open stream: No error in F:\xampp\htdocs\php\webCrawl\crawl.php images下如果没有这个文件则会创建,存在则覆盖,为什么failed.这是因为文件名7d5636
mysql判断是否包含某个字符的方法用locate 是最快的,like 最慢.position一般实战例子:select * from historydatawhere locate('0',opennum) and locate('1',opennum)order by number desc limit 10; 方法一:locate(字符,字段名)使用locate(字符,字段名)函数,如果包含,返回>0的数,否则返回0 , 它的别名是 position inselect * from 表名
--- The error occurred in EmptyMapping.xml. --- The error occurred while applying a parameter map. --- Check the queryEventStatisticsVO-InlineParameterMap. --- Check the statement (query failed). --- Cause: java.sql.SQLSyntaxErrorException: ORA-00911