SELECT C.ORG_SHORTNAME, B.USER_NAME, ROW_NUMBER () OVER ( PARTITION BY B.ORG_ID ORDER BY A.TOTAL_SCORE DESC ) CNO, A.TOTAL_SCORE, A.USER_ID FROM T_INDIVIDUAL_RANKING A INNER JOIN T_USER B ON A.USER_ID = B.USER_ID INNER JOIN SYS_ORG C ON C.ORG_ID = B.
select a.id as aid,b.id as bid,a.city,a.cang,a.sid,a.time as atime,b.time as btime,a.price as aprice,b.price as bprice,a.pm as apm,b.pm as bpm from (select id,city,cang,sid,time,price,@rank:=@rank+1 as pm from cai,(SELECT @rank:=0) B group by id,ci
1 前言 项目中排行榜刚好需要查数据库表然后给出编号,方案一,可以按条件查找出来,然后再按数组序号给编号,但是如果要查表出来直接看,就不太够用了:方案二,就是用代码帮忙编号.参考了网上一些代码,然后发现方法都有一个样的,然后这边只是作为记录使用,方便查找. 2 代码 SELECT province_id, province_name, gdp, (@i :=@i + 1) AS No FROM province, (SELECT @i := 0) AS it ORDER BY gdp DESC
查询表table1里字段id小于10的所有数据,并且让数据根据id降序排列,然后得到第一条数据 select * from (select * from table1 where id<10 order by id desc ) where rownum=1 注意:desc可以省略,默认的就是desc
demo: select * from ( select * from DEV_REG_CFG_CAMERA where 1 = 1 order by unid asc) where rownum < 3001 minus select * from ( select * from DEV_REG_CFG_CAMERA where 1 = 1 order by unid asc) where rownum < 1 minus是差集的意思,. 以上sql的意思是,查询DEV_REG_CFG_CA
项目开发中,我们有时会碰到需要分组排序来解决问题的情况:1.要求取出按field1分组后,并在每组中按照field2排序:2.亦或更加要求取出1中已经分组排序好的前多少行的数据 这里通过一张表的示例和SQL语句阐述下oracle数据库中用于分组排序函数的用法.1.row_number() over()row_number()over(partition by col1 order by col2)表示根据col1分组,在分组内部根据col2排序,而此函数计算的值就表示每组内部排序后的顺序编号(组
方法一 select t1.a,t1.b,t1.c from test t1 inner join (seelct a,max(b) as b from test group by a) t2 on t1.a=t2.a and t1.b=t2.b 方法二 select * from (select t.*, row_number() over(partition by 分组字段 order by 排序字段 desc ) rnfrom tablename t )where rn=1 方法三 (不一